CArbon has an atomic number of 6. There are therefore only 2 electrons in C4+
In a Co2+ ion, cobalt has two fewer electrons than its neutral state, so it loses two electrons. Cobalt in its neutral state has 7 unpaired electrons. Upon losing two electrons, the Co2+ ion has 5 unpaired electrons.
Cr and Fe have four unpaired electrons in their 2 plus ions.
Antimony (Sb) has an atomic number of 51, and its electron configuration is [Kr] 5s² 4d¹⁰ 5p³. In the Sb³⁺ oxidation state, it loses three electrons, typically from the 5p and 5s orbitals, resulting in the configuration [Kr] 4d¹⁰. Consequently, Sb³⁺ has no unpaired electrons, as all its electrons are paired in the filled 4d subshell.
b. Fe3 plus ions
The magnetic moment can be calculated using the formula ( \mu = \sqrt{n(n+2)} ), where ( n ) is the number of unpaired electrons. For Fe³⁺, which has a configuration of ( [Ar] 3d^5 ), there are 5 unpaired electrons, giving a magnetic moment of approximately ( \mu_{Fe^{3+}} \approx 5.92 ). For Co²⁺, with a configuration of ( [Ar] 3d^7 ), there are 3 unpaired electrons, resulting in a magnetic moment of about ( \mu_{Co^{2+}} \approx 3.87 ). Therefore, the ratio of the magnetic moments ( \mu_{Fe^{3+}} : \mu_{Co^{2+}} ) is approximately ( 5.92 : 3.87 ) or roughly ( 1.53 : 1 ).
In the element bromine (Br), there is only 1 unpaired electron. It has 7 valence electrons, so 3 pairs, plus an unpaired electron.
In a Co2+ ion, cobalt has two fewer electrons than its neutral state, so it loses two electrons. Cobalt in its neutral state has 7 unpaired electrons. Upon losing two electrons, the Co2+ ion has 5 unpaired electrons.
There are 4 unpaired electrons in the ground state electron configuration of an Fe atom. These 4 unpaired electrons are in the 3d subshell.
Cr and Fe have four unpaired electrons in their 2 plus ions.
There is merely one unpaired electron in Potassium. The electron configuration of potassium is [Ar]4s^1. This means that potassium has all the electrons of argon, plus one more in the 4s orbital. All the electrons of argon are paired, so the one electron in the 4s orbital is the only unpaired electron.
No, NH4+ is not a radical. It is an ion called ammonium, composed of one nitrogen atom and four hydrogen atoms, with a positive charge. A radical is a species with unpaired electrons, while NH4+ has no unpaired electrons.
Yes, aluminum (Al) is paramagnetic because it has unpaired electrons, which causes it to be weakly attracted to a magnetic field.
N2+ and N2- I just did it on mastering chem and it worked I'm pretty sure its because when you count the valence electrons in N2+ and N2- you get 9 and 11 respectively because these are odd there has to be an unpaired electron in each
b. Fe3 plus ions
phosphorus (P) as it has three unpaired electrons.
The magnetic moment can be calculated using the formula ( \mu = \sqrt{n(n+2)} ), where ( n ) is the number of unpaired electrons. For Fe³⁺, which has a configuration of ( [Ar] 3d^5 ), there are 5 unpaired electrons, giving a magnetic moment of approximately ( \mu_{Fe^{3+}} \approx 5.92 ). For Co²⁺, with a configuration of ( [Ar] 3d^7 ), there are 3 unpaired electrons, resulting in a magnetic moment of about ( \mu_{Co^{2+}} \approx 3.87 ). Therefore, the ratio of the magnetic moments ( \mu_{Fe^{3+}} : \mu_{Co^{2+}} ) is approximately ( 5.92 : 3.87 ) or roughly ( 1.53 : 1 ).
The number of electrons is 10.