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To determine the number of valence electrons in ammonium bromide (NH4Br), we first consider the individual components: nitrogen (N) has 5 valence electrons, each hydrogen (H) has 1 valence electron (totaling 4 for four hydrogens), and bromine (Br) has 7 valence electrons. Adding these together gives us 5 (from N) + 4 (from H) + 7 (from Br) = 16 valence electrons in total for NH4Br.

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