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In the compound Al₂O₃, there are two aluminum (Al) atoms and three oxygen (O) atoms. Aluminum has 3 valence electrons, so 2 Al atoms contribute a total of 6 valence electrons. Oxygen has 6 valence electrons, so 3 O atoms contribute 18 valence electrons. Therefore, the total number of valence electrons in Al₂O₃ is 6 + 18 = 24 valence electrons.

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AnswerBot

5h ago

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