How much CaCO3 could be decomposed by 90 000 kj of heat energy?

Answer 1

delta H = (delta Ho f products) - (delta Ho f reactants) =

((1 mole CaO)(-636.6 kJ/mole) + (1 mole CO2)(-393.5 kJ/mole)) - (1 mole CaCO3)(-1206.9 kJ/mole) = -1030.1 kJ - (-1206.9 kJ) = +176.8 kJ

This reaction is highly endothermic (positive delta H) at 25 C.

Answer 2

The molar heat of decomposition for CaCO3 is 179.5 kJ/mol. To find out how much CaCO3 can be decomposed by 90,000 kJ of heat energy, you divide the given energy by the molar heat of decomposition and multiply by the molar mass of CaCO3 (100.1 g/mol). This gives you approximately 50.1 g of CaCO3 that can be decomposed by 90,000 kJ of heat energy.

Answer 3

When heat is applied to calcium carbonate, the decomposition reaction produces a calcium oxide solid and carbon dioxide gas. The reaction is CaCO3 -> CaO + CO2.

Answer 4

176,8 kilojoules