As the molar mass of water is 18 g/mol (1*2 H + 16 O) 10 moles*18 g/mole=180 grams.
10H2O = 10 H2O so there will be 10 moles of water
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
10 moles of water (molar mass 18.0 g/mol) in 180 g, because 180 /18.0 = 10
10 liters = 10 kg (22.05 lbs) of water, since water has a density of 1kg/L.
For every mole of C3H8 that reacts, 4 moles of water are formed. Therefore, 5.0 moles of C3H8 will form 5.0 x 4 = 20 moles of water. To convert moles to molecules, you would then multiply by Avogadro's number (6.022 x 10^23 molecules/mol). So, 20 moles of water would equal 20 x 6.022 x 10^23 = 1.2044 x 10^25 molecules of water.
10 GRAMS
180 grams of water is 10 moles of water.
It weighs 10 grams
10H2O = 10 H2O so there will be 10 moles of water
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
Write out the equation first: 10H2 + 10O2 --> xH2O Since there are 2 moles of Hydrogen for every mole of Oxygen and equal moles of both are given, the Hydrogen limits the reaction as the limiting reactant. 10 moles of Hydrogen can make 10 moles of H2O with 5 moles of Oxygen left over. Think of it logically: H2 is two hydrogen atoms and water needs two hydrogen atoms, so it is a one-to-one reaction.
10 moles of water (molar mass 18.0 g/mol) in 180 g, because 180 /18.0 = 10
10 kg = 22 lbs
25 pounds
About 10% more for the same volume.
1 mole of water is 18g. 36g of water is thereforeequivalent to 2 moles. 2 moles of water contains 4 moles of hydrogen and 2 moles of oxygen and so there are6 moles of atoms in 2 moles of water. 6 moles of atoms x (3.6x10^24) = 36.1x10^24 atoms
10 liters = 10 kg (22.05 lbs) of water, since water has a density of 1kg/L.