To calculate the energy required to melt 390 grams of ice at 0°C, you can use the formula: ( Q = m \times L_f ), where ( Q ) is the energy, ( m ) is the mass in grams, and ( L_f ) is the latent heat of fusion for ice, which is approximately 334 J/g. Thus, ( Q = 390 , \text{g} \times 334 , \text{J/g} = 130,260 , \text{J} ). Therefore, melting 390 grams of ice requires about 130,260 joules of energy.
Heat because Ice and water would thaw out and begin to heat up
The energy required to melt ice is known as the heat of fusion, which is about 334 joules per gram. Therefore, it would take approximately 3340 joules of energy to melt 10g of ice.
To get ice to its melting point, it must absorb 334 joules of energy per gram of ice. So, for 150 grams of ice, the total energy required would be 50,100 joules (334 J/g * 150 g).
To convert ice to water on the moon, energy is needed to break the hydrogen bonds holding the water molecules together in the solid ice lattice. This process requires the input of heat energy to overcome the enthalpy of fusion of water, which is approximately 334 joules per gram.
It depends upon the condition of the ice and the environment it is in. For example, a block of ice in room temperature does not give off energy - to the contrary, it absorbs energy as it melts. . But a block of ice at -5oC that is set in freezer that is -20oC will give off its thermal energy until the block of ice's temperature falls to the freezer's temperature.
About three hundred and ninety grams.
Heat because Ice and water would thaw out and begin to heat up
The energy required to melt ice is known as the heat of fusion, which is about 334 joules per gram. Therefore, it would take approximately 3340 joules of energy to melt 10g of ice.
To find out how much ice remains, we first need to determine how much energy is needed to raise the temperature of the ice to 0°C, then melt the ice at 0°C, and finally warm the resulting water from 0°C to some final temperature. Given the data you provided, we can divide the energy absorbed (4.50 kJ) by the heat of fusion and specific heat capacity of ice to determine how much ice remains.
The amount of energy required to melt ice can be calculated using the equation: energy = mass of ice * heat of fusion. The heat of fusion for ice is 334 J/g, so for 32.0 g of ice, the energy required would be 32.0 g * 334 J/g = 10,688 J.
To get ice to its melting point, it must absorb 334 joules of energy per gram of ice. So, for 150 grams of ice, the total energy required would be 50,100 joules (334 J/g * 150 g).
To melt 1 gram of ice at 0°C, it requires 334 joules of energy. So for g grams of ice, the energy needed would be g multiplied by 334 joules.
To calculate the energy consumed in thawing ice, we use the formula: energy = mass x heat of fusion. The heat of fusion for ice is 334 J/g. Plugging in the values, we get: energy = 4.3g x 334 J/g = 1428.2 J. So, it would consume 1428.2 Joules of energy to thaw a 4.3g ice.
The energy needed to change ice into water is called the heat of fusion. For ice, this value is around 334 joules per gram. So, for 3 grams of ice, the energy gained when it changes to water would be around 1002 joules (334 joules/gram * 3 grams).
A calorie is the amount of energy needed to heat 1 gram of water by 1 degree Celsius. So you can't burn a calorie.
It takes about 334 J/g to melt ice. So, to melt a 16.87 g ice cube, you would need about 5635.58 J of energy.
The energy required to thaw ice can be calculated using the specific heat capacity of ice (2.09 J/g°C) and the heat of fusion of ice (334 J/g). To thaw 4.3 g of ice, the energy consumed would be the sum of the energy needed to raise the ice from 0°C to its melting point and the energy needed to melt the ice. The total energy consumed would be around 1,434.1 Joules.