765/137.32=5.57
5.57(1270/4)= 1769 kj
P4 (s) + 6Cl2 (g) -> 4PCl3 (l)
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
3Cl2(g) + 6OH-(aq) --> ClO3-(aq) + 5Cl-(aq) + 3H2O(l)
The balanced chemical equation for the reaction is: P4 (s) + 6Cl2 (g) -> 4PCl3 (s). To find the limiting reactant, we need to calculate the moles of P4 and Cl2 using their molar masses first. Then, we compare the amounts of PCl3 that can be produced from each reactant, and the smaller value (in moles) will be the limiting reactant. Finally, convert the moles of PCl3 to grams.