To calculate the energy required to raise the temperature of 3 kg of iron from 20°C to 25°C, you can use the formula:
[ Q = mc\Delta T ]
where ( Q ) is the heat energy, ( m ) is the mass (3 kg), ( c ) is the specific heat capacity of iron (approximately 450 J/kg°C), and ( \Delta T ) is the change in temperature (5°C).
Plugging in the values:
[ Q = 3 , \text{kg} \times 450 , \text{J/kg°C} \times 5 , \text{°C} = 6750 , \text{J} ]
Therefore, 6750 joules of energy is required.
414 kJ
2200 kj
To calculate the energy required to vaporize 2 kg of copper, you need to use the specific latent heat of vaporization for copper, which is approximately 300,000 J/kg. The total energy (Q) can be calculated using the equation Q = m * L, where m is the mass (2 kg) and L is the latent heat of vaporization (300,000 J/kg). Thus, Q = 2 kg * 300,000 J/kg = 600,000 J. Therefore, 600,000 joules of energy is required to vaporize 2 kg of copper.
In chemical symbols, the equation would be: 6CO2 + 6H20 + light energy -----> C6H12O6 + 6O2 In words, the equation would be: Carbon Dioxide + Water + light energy -----> glucose (sugar) + oxygen
When an enzyme is cooled below its optimal temperature, its activity decreases as the rate of enzymatic reactions slows down. This is due to reduced kinetic energy and molecular collisions required for the enzyme-substrate complex formation. Eventually, at low enough temperatures, the enzyme may denature, losing its active conformation and rendering it non-functional.
1935 JSource: Apex
414 kJ
energy in = energy out
The reaction is spontaneous below 554.8/0.1975 K.
The heat of vaporization of gold is 158 kJ/kg. To find the total energy required to vaporize 2 kg of gold, you can use the equation: Energy = mass * heat of vaporization. Substitute the values to get: Energy = 2 kg * 158 kJ/kg = 316 kJ. Therefore, 316 kJ of energy is required to vaporize 2 kg of gold.
The specific heat capacity of iron is about 0.45 J/g°C. To raise the temperature of 3 kg of iron by 5°C, you would use the equation Q = mcΔT, where m is the mass (3 kg), c is the specific heat capacity (0.45 J/g°C), and ΔT is the change in temperature (5°C). Therefore, the energy required would be around 6,750 Joules.
Well what is the baked item?
ground temperature below freezing, and air temperature slightly above freezing.
To determine the temperature range at which the decomposition of KClO4 is spontaneous, you would need the values for the standard Gibbs free energy change (ΔG°) and the equilibrium constant (K). By using the equation ΔG = -RTlnK and taking into account that ΔG = 0 for a reaction at equilibrium, you can rearrange to solve for the temperature range where decomposition is spontaneous.
2200 kj
No. Hypothermia is caused when an organism's temperature drops below the temperature required for normal body functions.
When kept in the refrigerator, a temperature at or below 40° F (4° C) is required.