To vaporize gold, we need to consider its molar enthalpy of vaporization. The molar enthalpy of vaporization of gold is approximately 334 kJ/mol. Since the molar mass of gold is about 197 g/mol, vaporizing 2 kg (2000 g) of gold requires:
( q = \frac{2000 , \text{g}}{197 , \text{g/mol}} \times 334 , \text{kJ/mol} \approx 3,385 , \text{kJ}. )
Thus, approximately 3,385 kJ of energy is required to vaporize 2 kg of gold.
To calculate the energy required to vaporize 2 kg of aluminum, we use the heat of vaporization of aluminum, which is approximately 10,900 J/kg. Therefore, the energy required is 2 kg × 10,900 J/kg = 21,800 J, or 21.8 kJ. This is the amount of energy needed to convert 2 kg of aluminum from a liquid to a vapor at its boiling point.
Enthalpy is used to calculate the energy required to vaporize a volume of liquid by applying the concept of latent heat of vaporization, which is the amount of energy needed to convert a unit mass of liquid into vapor without changing its temperature. The total energy required for vaporization can be calculated by multiplying the mass of the liquid by the specific enthalpy of vaporization (ΔH_vap) at the given temperature. This relationship allows us to determine the total energy input necessary to achieve complete vaporization of the liquid.
When the energy is required to vaporize liquid water, the molecules are highly agitated and brake free to become vapor through the state of latent heat of vaporization, then the energy is removed from the liquid and the temperature is reduced.
a gas
When a substance is below the triple point, the equilibrium will be between solid and vapor rather than solid/liquid or liquid/vapor. Sublimation is the direct change from solid to vapor without any intermediate phase change. The latent heat of sublimation is the energy required to change a given quantity of solid into the vapor at equilibrium. It is analogous to (but not the same as) latent heat of melting (energy required to melt the solid to liquid) and latent heat of vaporization (energy required to change a liquid into a gas).
The heat of fusion is used to first convert the volume of liquid to its solid form, then the heat of vaporization is used to convert the solid to vapor. By summing the two energy values, you can calculate the total energy required to vaporize the liquid volume.
To calculate the energy required to vaporize 2 kg of aluminum, we use the heat of vaporization of aluminum, which is approximately 10,900 J/kg. Therefore, the energy required is 2 kg × 10,900 J/kg = 21,800 J, or 21.8 kJ. This is the amount of energy needed to convert 2 kg of aluminum from a liquid to a vapor at its boiling point.
Any addition of thermal energy to a saturated liquid will cause it to vaporize. Any subtraction of thermal energy from a saturated vapor will cause it to condense.
The energy needed to completely vaporize a mole of a liquid
The energy required to vaporize a volume of liquid can be calculated using the heat of vaporization, which is the amount of energy needed to convert a unit mass of liquid into vapor at a constant temperature. This energy is typically provided by sources such as electricity or heat, rather than hydrogen fusion. Hydrogen fusion, on the other hand, is a nuclear reaction that powers stars and can be used to produce large amounts of energy through reactions like those in the Sun.
Vaporize Evaporate
Energy must be added to liquid water so that it reaches the boiling point, at which point the water will vaporize into water vapor.
The word that means convert into vapor is "vaporize".
When the energy is required to vaporize liquid water, the molecules are highly agitated and brake free to become vapor through the state of latent heat of vaporization, then the energy is removed from the liquid and the temperature is reduced.
Vapourous is the adjective related to the word vapour. Adjectives describing vapour include water, mysterious, and eerie.
The noun forms of the verb to vaporize are vaporizer, vaporization, and the gerund, vaporizing.A related noun form is vapor.
Yes, the heat of vaporization for water is equal in magnitude but opposite in sign to the heat of condensation. This means that the amount of energy required to vaporize water is the same as the amount of energy released when water vapor condenses back into liquid water.