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Assuming it's a sphere, the volume of the asteriod is 4pi/3 x (100,000)3 cubic meters. Let's assume it's half rock and half ice (by volume). The mass of rock is then 2pi/3 x (100,000)3 cubic meters times ... well, it depends on the KIND of rock, but 2.5 tonnes per cubic meter is a fairly representative value for lots of kinds of rock. The mass of ice is the same volume figure, but the density of ice is about 0.9 tonnes per cubic meter.

The specific heat of rock again depends on the type of rock, but just as a rough estimate let's say 200 calories per kilogram kelvin, which is kind of in the middle of the range. The specific heat of ice is actually dependent on the temperature, but as a rough average over the range in question let's call it 400 calories per kilogram kelvin.

So for the rock that's roughly 2 x 1015 cubic meters x 2.5 tonnes/cubic meter x 200 kcal/tonne kelvin, which comes out to a bit more than 1018 kcal per kelvin, and since we're heating it by 250 kelvin, let's call it 2.6x1023 calories. Multiply by 4.184 to get joules and it's about 1.1x1024J for the rock.

The ice part is a little trickier because there's a phase transition in there. I come up with about 7x1023J to get it to 273K. Heating the liquid water from 273K to 293K will bring the total up to about 9x1023J. However, melting that much ice will take about 6x1023J. All in all, it turns out the water part takes about 1.5x1024J total.

All told (and keeping more significant figures than I can really justify), we're looking at about 2.6x1024 J. There's a LOT of room for variation in there, depending on what kind of rock it is exactly and what the relative proportions of ice and rock are, but somewhere in the low single digit yottajoules is the right ballpark.

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