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The heat of fusion for water is 6.02 kJ/mol. So we need to convert 1 gram of water into moles of water: 1 g H2O x 1 mol H2O/18.02 g H2O = 0.055 moles H2O Now we can find the heat released from freezing those 0.055 moles: 0.055 moles H2O x 6.02 kJ/1 mol H2O = 0.334 kJ of heat released Of course if we use the proper number of significant figures (since you only wrote 1g) it would be 0.3 kJ of heat released.

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