The heat of fusion for water is 6.02 kJ/mol. So we need to convert 1 gram of water into moles of water: 1 g H2O x 1 mol H2O/18.02 g H2O = 0.055 moles H2O Now we can find the heat released from freezing those 0.055 moles: 0.055 moles H2O x 6.02 kJ/1 mol H2O = 0.334 kJ of heat released Of course if we use the proper number of significant figures (since you only wrote 1g) it would be 0.3 kJ of heat released.
Approximately 30,000 gallons of water is required to condense one ton of steam.
water has a high heat of vapourization.it absorbs much heat as it changes from liquid to gas.it has the capacity of absorbing heat with minimum of change in its own temperature
To change the temperature of water from 27ºC to 32ºC will depend on the mass of water that is present. Obviously, the more water, the more heat it will take. This can be calculated as follows:q = heat = mC∆T where m is the mass of water; C is sp. heat = 4.184 J/g/deg and ∆T is 5ºC (change in temp).
The equation is q = mC∆T where q is the heat; m is the mass of water; C is the specific heat of water (1 cal/g/deg); and ∆T is the change in temperature.
This heat is: 5 x 4,18 x m = 20,9 x m (in calories) where m is the mass of water.
55 Ml.
Heat required to have such a change of state is called latent heat. If L J/kg is the latent heat per kg of water then for M kg of water we need M* L joule of heat energy
Approximately 30,000 gallons of water is required to condense one ton of steam.
water has a high heat of vapourization.it absorbs much heat as it changes from liquid to gas.it has the capacity of absorbing heat with minimum of change in its own temperature
The amount of heat that must be removed from steam to change it to a liquid is the latent heat of vaporization of water, which is approximately 2260 kJ/kg at atmospheric pressure. This is the amount of energy required for water to change from a gas to a liquid state at a constant temperature.
To change the temperature of water from 27ºC to 32ºC will depend on the mass of water that is present. Obviously, the more water, the more heat it will take. This can be calculated as follows:q = heat = mC∆T where m is the mass of water; C is sp. heat = 4.184 J/g/deg and ∆T is 5ºC (change in temp).
To change 1 kg of ice at 0°C to water at 0°C, you would need 334 kJ of heat energy. This includes the heat required to raise the temperature of the ice to 0°C (latent heat of fusion) and then to melt it into water at 0°C.
The equation is q = mC∆T where q is the heat; m is the mass of water; C is the specific heat of water (1 cal/g/deg); and ∆T is the change in temperature.
The amount of heat energy transferred to hot water depends on various factors such as the initial and final temperatures of the water, the mass of the water, and the specific heat capacity of water. The formula to calculate heat energy transferred is: Q = mcΔT, where Q is the heat energy, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
If there is too much water, people are flooded out of their homes. If there is not enough water, you have drought, and that leads to heat stroke, thirst, and hunger.
This heat is: 5 x 4,18 x m = 20,9 x m (in calories) where m is the mass of water.
Heat capacity is the amount of heat something can take before it changes temperature by a degree. If we use water as an example, it is said to have a high heat capacity as you need to heat it a lot before it changes temperature at all. Latent means not yet existing. Latent heat is therefore referring to the amount of heat it would take something for it to change state. Water is said to have a high latent heat of vaporisation. That means that it takes a lot of heat to vaporise water. While heat capacity talks about how much heat something can take, latent heat talks about how much heat something requires to cause a change. Similar concepts but they have slight differences.