Within a day, i would say it's possible. Scientists have said that drinking 60 cups of water within an hour is enough to flood your system and kill you.
10 liters = 10 kg (22.05 lbs) of water, since water has a density of 1kg/L.
If you're talking about 10 liters of water and not percent, then 10 liters. But then you'll have 60 liters of mixture. It would be 2/5 or 0.4 x 50 = 20 this would make a mix of 20/50. Waterman
To reduce a 25% acid solution to 10%, the water needed can be calculated using the formula: (10 x (25-10))/(10) = 1.5 liters. So, 1.5 liters of pure water must be mixed with the 10 liters of 25% acid solution to reduce it to 10%.
10 kg of mass is equivalent to 10 liters of water, assuming the water has a density of 1 kg/L.
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl it will take a lot of thinking. The answer to this question is 1.64L.
10 liters = 10 kg (22.05 lbs) of water, since water has a density of 1kg/L.
10 gallons of water is equivalent to approximately 37.85 liters.
It nearly 10 liters of water is wasted
10 milliliters! Not much.
10 cubic meters = 10,000 liters
30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.
10 kg = 22 lbs
If you're talking about 10 liters of water and not percent, then 10 liters. But then you'll have 60 liters of mixture. It would be 2/5 or 0.4 x 50 = 20 this would make a mix of 20/50. Waterman
10 liters if u have a day if u have a bath abd 4liters if not bath with2 liters of water
You can't convert pounds to liters. You need to know how much one liter of whatever you have weighs and then multiply that by 10. If the substance is water, 1 liter weighs about 2.2 lbs. So, 10 liters of water weighs 22 lbs.
To reduce a 25% acid solution to 10%, the water needed can be calculated using the formula: (10 x (25-10))/(10) = 1.5 liters. So, 1.5 liters of pure water must be mixed with the 10 liters of 25% acid solution to reduce it to 10%.
9 liters