Matter might look different after a physical change, but the kind of matter itself does not change. Its particles have not changed. They are just packed together differently.
To calculate the mass of water that would need to evaporate to dissipate 2000 kJ of heat, we need to use the heat of vaporization of water, which is 2260 J/g. By converting the energy to joules and dividing by the heat of vaporization, we find that approximately 884 grams (0.88 kg) of water would need to evaporate from the athlete's skin.
You would need to specify the material being measured, or the density of the material, in order to convert a mass measurement like grams into a volume measurement like milliliters. However, for pure water at standard temperature and pressure, one milliliter of water has a mass of one gram, by definition.
Same as it is now, but instead of as much land mass . More water will evaporate to space and earth will be without water . That will happen when sun will become red giant
If water and carbonated liquid are exposed to same environmental conditions then water will evaporate faster by mass. However,, as the carbonated liquids contain a lot of CO2 so it may evaporate faster by volume.
By definition, it weighs 50 grams. A litre of water weighs a kilogram.
236.58824 grams
The remaining water in Kia's bottle has a mass of about 500 grams.
If you evaporate 10 grams of salt in 50 ml of water, all of the salt will remain once the water has completely evaporated. Evaporation only removes the water, leaving behind the salt.
450 grams is mass, if you want volume it's 450 millilitres
The answer will depend on how much water - a drop, a cupful, a bucketful, a whole lakeful or WHAT!
Mass can be measured in grams, not weight. The weight of 1 Imperial pint is approx 5.6 Newtons.
The mass of a standard stapler typically ranges from 200 grams to 500 grams.
If the water was pure and had no salt already mixed in it then the same 20 grams of salt would be left, as salt doesn't evaporates on the temperature at which water does evaporates.
To calculate the mass of water that would need to evaporate to dissipate 2000 kJ of heat, we need to use the heat of vaporization of water, which is 2260 J/g. By converting the energy to joules and dividing by the heat of vaporization, we find that approximately 884 grams (0.88 kg) of water would need to evaporate from the athlete's skin.
A liter of water has a mass of about one kg.
about 50 grams
39 grams is equivalent to....a mass of 39 grams !