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How many molecules are contained in 16.81 of Xe at STP?
To find the number of molecules in 16.81 grams of xenon (Xe) at standard temperature and pressure (STP), first calculate the number of moles using the molar mass of xenon, which is approximately 131.3 g/mol. The number of moles is 16.81 g / 131.3 g/mol ≈ 0.128 moles. Using Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol), the total number of molecules is 0.128 moles × (6.022 \times 10^{23}) molecules/mol ≈ (7.71 \times 10^{22}) molecules.
What is the theoretical mass of xenon tetrafluoride that should form when 130 G of xenon is reacted with 100 G of F2?
To determine the theoretical mass of xenon tetrafluoride that forms, first calculate the limiting reactant by converting the masses of xenon and fluorine to moles using their molar masses. Then, use the mole ratio from the balanced chemical equation (Xe + 2F2 -> XeF4) to find the limiting reactant. Finally, use the limiting reactant to calculate the theoretical mass of xenon tetrafluoride formed.
What is the noble gas notation for Xenon?
The noble gas notation for Xenon is [Kr] 4d^10 5s^2 5p^6. This notation represents the electron configuration of Xenon with the closest noble gas element, Krypton, in brackets followed by the configuration for Xenon.
What is the pronunciation of xenon in rebus form?
"Xenon" in rebus form would be "X" + "e" + "n" + "on," pronounced as "zee-non."
How do you write the structure for XeO3?
Xenon does not have to follow the octet rule because of its access to the 4d sublevel. The Lewis structure of XeO3 places a Xe in the center, double bonded to three O atoms and with one lone pair on the Xe.
How many moles of fluorine are in 3.2 moles of xenon hexafluoride?
There are 19.2 moles of fluorine in 3.2 moles of xenon hexafluoride. Xenon hexafluoride has 6 fluorine atoms in each molecule, so you multiply the moles of xenon hexafluoride by 6 to find the moles of fluorine.
How many xenon atoms are contained in 2.36 moles of xenon?
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
How many moles are in 57 grams of Xenon?
To find the number of moles in 57 grams of Xenon, divide the given mass (in grams) by the molar mass of Xenon. The molar mass of Xenon is 131.3 grams/mol. Therefore, 57 grams of Xenon is equal to 0.434 moles (57/131.3).
How many moles of xenon do 5.66 x 1023 atoms equal?
5.66 x 10^23 atoms of xenon is equal to 0.094 moles.
How many grams are in 44.3 moles of Xenon?
To convert moles to grams, you need to use the molar mass of Xenon, which is 131.3 g/mol. Multiplying 44.3 moles by the molar mass gives you a total of 5812.59 grams of Xenon.
How many moles are there in 5 g of xenon Xe?
Approx 0.46 moles.
How many moles of xenon do 5.66x1023 atoms equal?
5.66 X 1023 atoms of xenon (1 mole Xe/6.022 X 1023) = 0.940 moles of xenon ------------------------------
How many moles are in xenon?
The answer depends on the quantity of Xenon.
A container that holds 20.0 grams of neon gas under the same conditions how many grams of xenon would the container hold?
If both gases are at the same conditions of temperature, pressure, and volume, then the number of moles of neon and xenon in the container would be the same. Since xenon is a heavier gas than neon, the container would hold less xenon by mass compared to neon for the same number of moles. Neon's molar mass is 20.18 g/mol, while xenon's molar mass is 131.29 g/mol, suggesting the container would hold less xenon by mass compared to neon.
What is the mass of 1.5E-2 moles of xenon tetra- fluoride?
To find the mass of 1.5E-2 moles of xenon tetrafluoride (XeF4), you would multiply the number of moles by the molar mass of XeF4. The molar mass of XeF4 is approximately 207.29 g/mol. Therefore, the mass of 1.5E-2 moles of XeF4 would be approximately 3.11 grams.
What is the mole fraction of xenon in a mixture that contains 0.584 g of xenon 86.40 g of argon and 3.62 g of neon?
Convert all to moles: 0.584g Xe = 0.0044mol. 86.4g Ar = 2.16mol. 3.62g Ne = 0.18 mol. Total moles = 0.0044 + 2.16 + 0.18 = 2.34mol. Mole fraction = moles of 1 component divided by total moles of all components, so 0.0044/2.34 = 0.0019.
How many moles are in xenon hexafluoride?
The answer depends on the quantity of XeF6
