It depends on the amount of solute.
You can separate KNO3 from its aqueous solution by a process called evaporation. Simply heat the solution to evaporate the water, leaving behind solid KNO3. This method exploits the fact that KNO3 has a much higher boiling point compared to water.
Sorry, I mean a HCl solution in water, not Cl.
The amount of water needed to dissolve 25kg of salt depends on the concentration of the salt solution desired. In general, 25kg of salt would require more than 25kg of water to fully dissolve, as salt has a limited solubility in water. Additional water would be needed to create a saturated salt solution.
To calculate the amount of water needed, first determine the mass of formaldehyde in the final solution. Since the solution is 40.0% formaldehyde by mass, the mass of formaldehyde is 40.0% of the final solution mass. Subtract the mass of formaldehyde in 425 g from this value to find the mass of water needed to prepare the solution.
You need min. 5,63 g cerium sulfate.
There are many chemicals aqueous with water, for example: Sodium Chloride (basic table salt) is. To find more check with solubility rules, if it says the the substance is soluble, then it is aqueous with water.
Difference Between Liquid and Aqueous• Liquid is a state of matter, while aqueous is a special type of liquid formed by dissolving a compound in water• All aqueous solutions are liquids, but not all liquids are aqueous solutionsPlease see related link
You can separate KNO3 from its aqueous solution by a process called evaporation. Simply heat the solution to evaporate the water, leaving behind solid KNO3. This method exploits the fact that KNO3 has a much higher boiling point compared to water.
The solubility of sodium chloride in water is 360,0 g/L at 20 0C.
To dilute the 3.5 M H2SO4 solution to 2 M, you need to add water. Use the formula M1V1 = M2V2, where M represents molarity and V represent volume. For this situation, you'll end up adding 75 ml of water to the initial 75 ml of 3.5 M H2SO4 solution to achieve a final 2 M concentration.
percent concentration = (mass of solute/volume of solution) X 100 To solve for mass of solute, mass of solute = (percent concentration X volume of solution)/100 So, mass of solute = (10% X 100mL)/100 = 10g
That depends. Have you extracted with water and a volatile acid? Have you then evaporated the water from said solution? Have you then made another aqueous solution and adjusted the pH to 9.0-9.2? Have you then filtered, kept the filtrate and discarded the solution? Have you then dried this out? This is pretty much the rawest product you would want to inject.
The strength of a base is how much it dissociates in water.
Sorry, I mean a HCl solution in water, not Cl.
The amount of water needed to dissolve 25kg of salt depends on the concentration of the salt solution desired. In general, 25kg of salt would require more than 25kg of water to fully dissolve, as salt has a limited solubility in water. Additional water would be needed to create a saturated salt solution.
2.5 g of Nacl is to be dissolve in 100ml of water gives 10ppm of Na solution.
first, table salt is not a saturated solution, because you can't see through it. it needs to be liquid, and solutions become a saturated solution when you put as much as you can in the water. now, it's a solution and it is saturated.