The work done (W) in moving a charge (Q) through a potential difference (ΔV) is given by the formula ( W = Q \times \Delta V ). In this case, the charge is 3 coulombs, and the potential difference is ( 125 , \text{V} - 115 , \text{V} = 10 , \text{V} ). Therefore, the work done is ( W = 3 , \text{C} \times 10 , \text{V} = 30 , \text{J} ).
Electrical current is the number of elementary charge units (coulombs) that pass by a given point in one second. Current, measured in amperes, is coulombs per second. Electrical voltage is the "pressure" behind that current. Voltage, measured in volts, is joules per coulomb.
The potential difference between -1 and 2 volts is 3 volts. A potential difference of 3 volts means that there is an electric field pushing a charged particle from the -1 volt point to the 2 volt point.
The work done in moving a charge across a potential difference is given by the formula: work = charge * potential difference. Therefore, the work done in moving a charge of 2 C across a potential difference of 12 volts is 24 Joules.
Yes, current is the flow of electric charge, typically carried by electrons in a conductor. It is measured in amperes and represents the rate at which electrons pass through a given point in a circuit.
Electric potential is a scalar quantity that represents the amount of electric potential energy per unit charge in a specific location in an electric field. It is a measure of the work done in moving a unit positive charge from infinity to that specific location without producing an acceleration. The unit for electric potential is volts (V).
Well, darling, to calculate the work done in moving a charge, you use the formula: work = charge x change in voltage. So, for a charge of 3 coulombs and a voltage change of 10 volts, the work done would be 30 joules. Easy peasy lemon squeezy!
Volts. 12.6 volts = Full Charge 12.4 volts = 75% Charge 12.2 volts = 50% Charge 12.2 volts = 25% Charge
12.6 volts = 100% Charge 12.4 volts = 75% 12.2 volts = 50% 12.0 volts = 00%
To calculate the energy expended in moving a charge through a potential difference, you can use the formula: Energy (E) = Charge (Q) × Potential Difference (V) Given: Charge (Q) = 20 Coulombs Potential Difference (V) = 0.5 Volts Plugging in the values: E = 20 C × 0.5 V E = 10 Joules Therefore, the energy expended in moving a 20 Coulomb charge through a potential difference of 0.5 Volts is 10 Joules.
100% charge = 12.6 volts 75% charge = 12.4 volts 50% charge = 12.2 volts 25% charge = 12.0 volts
12.6 volts at 100% charge 12.4 volts at 75% charge 12.2 volts at 50% charge 12.0 volts at 25% charge
Volts
12.6 volts 100% charge 12.4 volts 75% charge 12.2 volts 50% charge 12.0 volts 25% charge Any less and the battery is essentially dead.
As read from the battery with a digital volt meter with engine off. 12.6 volts = 100% charge 12.4 volts = 75% charge 12.2 volts = 50% charge 12.0 volts = 25% charge
A fully charged 12 volt automobile battery will read 12.6 volts with the engine not running and 13.5 to 15.5 volts with the engine running. It will read 12.4 volts with a 75% charge, 12.2 volts with a 50% charge and 12.0 volts indicates a 25% charge.
A fully charged 12 volt battery with engine not running, ignition off will read 12.6 volts at 100% charge. 12.4 volts at 75% charge. 12.2 volts at 50% charge. 12.0 volts at 25% charge.
110 volts