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Which contain more heat 1 kg of steam at 373k or 1 kg of water at 373k?
1 kg of steam at 373 K contains more heat than 1 kg of water at 373 K because steam has a higher specific heat capacity and latent heat of vaporization than water. This means more heat energy is required to convert water at 373 K into steam at 373 K.
What is the value of latent heat of vaporization of water?
The latent heat of vaporization of water is approximately 2260 kJ/kg at standard atmospheric pressure and temperature. This is the amount of energy required to change 1 kg of liquid water at its boiling point into steam at the same temperature.
What would you need to do to calculate the molality of 10 h of NaCl in 2 kg of water?
To calculate the molality of NaCl in 2 kg of water, first, you need to determine the number of moles of NaCl present. This can be done by using the formula: moles = mass (g) / molar mass (g/mol). Once you have the number of moles, you can calculate molality using the formula: molality (m) = moles of solute / mass of solvent (kg). In this case, the mass of the solvent is 2 kg of water.
Why 1 kg of steam at 100 degree c cointains more heat against 1 kg of water at same temperature?
The difference is the evaporation heat (or the 'equal' condensation heat)
Is a watermelon is heavier than a kilogram?
A gram of water and a gram of steam are attracted by the Earth with equal "heaviness". Steam is less *dense* than water, until you get up to thousands of atmospheres of pressure.... then it doesn't seem to matter.
Which contain more heat 1 kg of steam at 373k or 1 kg of water at 373k?
1 kg of steam at 373 K contains more heat than 1 kg of water at 373 K because steam has a higher specific heat capacity and latent heat of vaporization than water. This means more heat energy is required to convert water at 373 K into steam at 373 K.
How much heat gives 1 kg of steam?
The amount of heat required to convert 1 kg of steam to water at its boiling point is known as the latent heat of vaporization. For water, this amount is approximately 2260 kJ/kg.
What is latent heat evaporation?
Latent heat of evaporation of water to steam is 2270 KJ/Kg
What is dryness fraction with answer?
If the water content of the steam is 5% by mass, then the steam is said to be 95% dry and has a dryness fraction of 0.95.Dryness fraction can be expressed as:ζ = ws / (ww + ws) (1)whereζ = dryness fractionww = mass of water (kg, lb)ws = mass of steam (kg, lb)GAJANAN Nalegaonkar
How much steam will produce if 1 kg of water used at 170 degree temperature?
The answer will depend on the units for the temperature.
How much is1 tone steam to cubic meter?
for converting cubic meter to ton , density or specific volume is needed. specific volume unite is m3/kg. steam cubic meter/ (cubic meter/kg)= steam (kg ) /1000= tone of steam
How much energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature?
The heat of vaporization for mercury is about 59.11 kJ/kg. To convert this to joules/kg, multiply by 1000 to get 59,110 J/kg. Therefore, for 0.06 kg of mercury, the energy released when condensed to a liquid at the same temperature would be 0.06 kg * 59,110 J/kg = 3,546.6 Joules.
What is the value of latent heat of vaporization of water?
The latent heat of vaporization of water is approximately 2260 kJ/kg at standard atmospheric pressure and temperature. This is the amount of energy required to change 1 kg of liquid water at its boiling point into steam at the same temperature.
How much energy is required to make 1 kg of steam from 1 ltr of water?
The answer will depend on the starting temperature of the water. It will also depend on the pressure.
What would you need to do to calculate the molality of 10 h of NaCl in 2 kg of water?
To calculate the molality of NaCl in 2 kg of water, first, you need to determine the number of moles of NaCl present. This can be done by using the formula: moles = mass (g) / molar mass (g/mol). Once you have the number of moles, you can calculate molality using the formula: molality (m) = moles of solute / mass of solvent (kg). In this case, the mass of the solvent is 2 kg of water.
What would you need to do to calculate the molality of 0.2 kg of NaCl on 3 Kg of water?
To calculate the molality of NaCl in water, first, determine the number of moles of NaCl by dividing the mass of NaCl (0.2 kg or 200 g) by its molar mass (approximately 58.44 g/mol). Then, divide the number of moles of NaCl by the mass of the solvent (water) in kilograms (3 kg). The formula for molality (m) is m = moles of solute / mass of solvent in kg.
Why 1 kg of steam at 100 degree c cointains more heat against 1 kg of water at same temperature?
The difference is the evaporation heat (or the 'equal' condensation heat)
