To make 15% alcohol from 40% alcohol you simply take 15cc of your 40% alcohol and put it into a graduated cylinder and fill the cylinder up the rest of the way with deionised water or distilled water to the 40cc mark on the graduated cylinder. you will then have 15% alcohol from 40%
Let x be the ounces of 15% alcohol solution. The amount of alcohol in the 15% solution is 0.15x, and the amount of alcohol in the 23% solution is 0.23(100 - x). Setting up the equation 0.15x + 0.23(100 - x) = 0.15(100) solves for x, which is approximately 38.5 ounces of the 15% alcohol solution needed.
It would flow toward the weaker solution. The intent of osmosis is to gain equilibrium, so the 15 percent solution would gain sugar content until, if you allowed the osmosis to go to completion, the two solutions had the same amount of sugar in them. "Going to completion" doesn't necessarily mean 20 percent concentration on both sides. If you were to make a gallon bag out of dialysis membrane, fill it with 15 percent solution and put a stirrer in it, then drop it into a 25,000-gallon reaction vessel full of 25 percent solution with a stirrer in it, you might wind up with 24.9999999999 percent sugar solution in both bags.
It depends, is the solution 15% salt or 15% saturatedwith salt? If it is 15% salt, is is 85% water. If it is 15% saturated, it is 5.385%.
To find the percent by volume of acetone in the solution, first calculate the total volume of the solution, which is 15 ml (acetone) + 28 ml (water) = 43 ml. The percent by volume of acetone is then calculated as (volume of acetone / total volume) × 100, which is (15 ml / 43 ml) × 100 ≈ 34.88%. Thus, the percent by volume of acetone in the solution is approximately 34.88%.
There are 48 mL of acid in 320 mL of a 15% acid solution. This is calculated by multiplying the volume of the solution by the percentage of acid in the solution: 320 mL x 0.15 = 48 mL.
Let x be the ounces of 15% alcohol solution. The amount of alcohol in the 15% solution is 0.15x, and the amount of alcohol in the 23% solution is 0.23(100 - x). Setting up the equation 0.15x + 0.23(100 - x) = 0.15(100) solves for x, which is approximately 38.5 ounces of the 15% alcohol solution needed.
Let a be the number of ounces of 25% alcohol required. Then, 25a + (30x9) = 28(9 + a) 25a + 270 = 252 + 28a 3a = 18 a = 6 Then 6 ounces of 25% alcohol + 9 ounces of 30% alcohol produces 15 ounces of 28% alcohol.
It depends on the temperature. At standard freezer temperatures, a solution of 15 percent alcohol is likely to freeze. Alcohol has a lower freezing point than water, so the exact temperature at which it freezes will depend on the specific type of alcohol used.
You have 6 litres of alcohol in 24 litres of water You need to add x litres to make 6 equal to 15% of 30 + x. 6 is 15% of 40, so x = 10
To find the volume percent of a component in a solution, divide the volume of that component by the total volume of the solution, then multiply by 100. The formula is: Volume Percent = (Volume of Component / Total Volume of Solution) × 100. For example, if you have 30 mL of alcohol in a 200 mL solution, the volume percent would be (30 mL / 200 mL) × 100 = 15%.
The alcohol content of a bottle of wine labeled as containing 15 percent wine is 15.
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
.95*(first alcohol(l)) + .15*(second alcohol(l))=.45(10) 1st+2nd=10l
It would flow toward the weaker solution. The intent of osmosis is to gain equilibrium, so the 15 percent solution would gain sugar content until, if you allowed the osmosis to go to completion, the two solutions had the same amount of sugar in them. "Going to completion" doesn't necessarily mean 20 percent concentration on both sides. If you were to make a gallon bag out of dialysis membrane, fill it with 15 percent solution and put a stirrer in it, then drop it into a 25,000-gallon reaction vessel full of 25 percent solution with a stirrer in it, you might wind up with 24.9999999999 percent sugar solution in both bags.
1.5 pints
Most use a 15% alcohol to 85% gasoline mixture.
15%