You add water to the container then you stir, the water and salt would form a solution and sand would settle on the bottom of the container. You get another container and place on a filter paper then you pour the water into it, which would lead to the sand staying in the filter paper and the solution, which is made of salt and water, would be left. Finally, you place the container on a source of heat which will cause the water to evaporate and salt staying in the container.
Now weigh the residue and find the percentage.
To find the percent by mass of the solution, first calculate the total mass of the solution, which is the sum of the mass of glucose and the mass of water: 50.0 g (glucose) + 1000.0 g (water) = 1050.0 g. The percent by mass of glucose in the solution is then calculated as (mass of glucose / total mass of solution) × 100 = (50.0 g / 1050.0 g) × 100 ≈ 4.76%. Therefore, the percent by mass of glucose in the solution is approximately 4.76%.
To find the concentration in mass percent, first calculate the total mass of the solution (50.0g NaCl + 150.0g water = 200.0g total). Then, divide the mass of NaCl by the total mass of the solution and multiply by 100 to get the concentration in mass percent: (50.0g NaCl / 200.0g total) * 100 = 25.0% NaCl.
1. Find the molar mass (MM) of the hydrate (cobalt acetate tetrahydrate).MM Co(C2H3O2)2: 177.02g (anhydrate)+ MM 4H2O: 72.06g (water)MM Co(C2H3O2)2 * 4H2O = 249.08g (hydrate)2. Find the percent water of hydrate. Divide the mass of water by the mass of hydrate (anhydrate + water = hydrate).72.06g249.08g x 100%Percent water of hydrate is 28.93%.Finding Molar Mass# atoms Element A * Atomic Mass Element A = Mass A# atoms Element B * Atomic Mass Element B = Mass B... etc.Add up all of the mass values and you have the molar mass of the substance.
To find the percent of 17g sucrose in 188g of water, first calculate the total mass: 17g (sucrose) + 188g (water) = 205g. Then, divide the mass of sucrose (17g) by the total mass (205g), and multiply by 100 to convert to a percentage. The percent of 17g sucrose in 188g of water would be roughly 8.29%.
1. Find the molar mass (MM) of the substances.MM FeSO4 = 151.91g+MM 7H2O = 126.11gMM FeSO4 x 7H2O = 278.02g2. Find the percent water of hydrate.Divide the mass of water by the mass of the hydrate; multiply result by 100%.126.11g278.02g x 100%Percent water of FeSO4 * 7H2O is 45.36%.Finding Molar Mass# atoms Element A x atomic mass Element A = Mass A# atoms Element B x atomic mass Element B = Mass B... etc.Add up all the mass values for the substance and you have the molar mass of the substance.
To calculate the percent water in a hydrate, you first determine the mass of water in the hydrate by subtracting the mass of the anhydrous compound from the mass of the hydrate. Then, divide the mass of water by the total mass of the hydrate and multiply by 100 to get the percentage.
To find the percent by mass of the solution, first calculate the total mass of the solution, which is the sum of the mass of glucose and the mass of water: 50.0 g (glucose) + 1000.0 g (water) = 1050.0 g. The percent by mass of glucose in the solution is then calculated as (mass of glucose / total mass of solution) × 100 = (50.0 g / 1050.0 g) × 100 ≈ 4.76%. Therefore, the percent by mass of glucose in the solution is approximately 4.76%.
To find the concentration in mass percent, first calculate the total mass of the solution (50.0g NaCl + 150.0g water = 200.0g total). Then, divide the mass of NaCl by the total mass of the solution and multiply by 100 to get the concentration in mass percent: (50.0g NaCl / 200.0g total) * 100 = 25.0% NaCl.
Percent by mass = (100) times (mass of the ingredient of interest) divided by (mass of the whole mixture)
mass (g) solute divided by total mass (g)times 100%total mass (g) = [mass solute + mass (g) solvent]54.0 / [128 + 54.0] = 29.6%
To calculate the percent by mass of an element in a compound, you divide the mass of the element by the total mass of the compound and then multiply by 100. This gives you the percentage of the compound's mass that is made up of that specific element.
1. Find the molar mass (MM) of the hydrate (cobalt acetate tetrahydrate).MM Co(C2H3O2)2: 177.02g (anhydrate)+ MM 4H2O: 72.06g (water)MM Co(C2H3O2)2 * 4H2O = 249.08g (hydrate)2. Find the percent water of hydrate. Divide the mass of water by the mass of hydrate (anhydrate + water = hydrate).72.06g249.08g x 100%Percent water of hydrate is 28.93%.Finding Molar Mass# atoms Element A * Atomic Mass Element A = Mass A# atoms Element B * Atomic Mass Element B = Mass B... etc.Add up all of the mass values and you have the molar mass of the substance.
To find the percent of 17g sucrose in 188g of water, first calculate the total mass: 17g (sucrose) + 188g (water) = 205g. Then, divide the mass of sucrose (17g) by the total mass (205g), and multiply by 100 to convert to a percentage. The percent of 17g sucrose in 188g of water would be roughly 8.29%.
1. Find the molar mass (MM) of the substances.MM FeSO4 = 151.91g+MM 7H2O = 126.11gMM FeSO4 x 7H2O = 278.02g2. Find the percent water of hydrate.Divide the mass of water by the mass of the hydrate; multiply result by 100%.126.11g278.02g x 100%Percent water of FeSO4 * 7H2O is 45.36%.Finding Molar Mass# atoms Element A x atomic mass Element A = Mass A# atoms Element B x atomic mass Element B = Mass B... etc.Add up all the mass values for the substance and you have the molar mass of the substance.
To calculate the mass percent of CaCl2 in water, first find the total mass by adding the mass of CaCl2 (5.0 g) and the mass of water (95.0 g), which equals 100.0 g. The mass percent of CaCl2 is then (5.0 g / 100.0 g) x 100% = 5.0%.
To calculate the mass percent of chlorine in chloroform (CHCl3), you would first find the molar mass of the compound, which is 119.38 g/mol. Then, determine the molar mass of chlorine in the compound, which is 35.453 g/mol. Calculate the mass percent of chlorine by dividing the molar mass of chlorine by the molar mass of the compound and multiplying by 100. In this case, the mass percent of chlorine in chloroform is about 29.7%.
70% water and 30%mass