How will you prepare a 500 micrograms per mililitre solution of BSA from a 1mgml solution?

Answer 1

First figure out how much substance is in 500 microliters of a 2 mg/L solution this is 0.0005 L X 2mg/L =0.001 mg Then figure out how much solution you need to get 0.001 mg which is 0.001 mg divided by 1 mg/mL which equals 0.001 mL or 1 microlitre.. So to make your solution you would add 1 microliter of your stock to 499 of water.

Answer 2

If you have 1000micrograms in a ml, you have 1 milligram per millilitre. You are making it to 100ml, so you need to multiply a milligram by 100. The answer is you weigh out 100mg and dissolve this in the specified volume.

Answer 3

To prepare a 500 micrograms per milliliter (µg/mL) solution of BSA from a 1 mg/mL solution, you will need to dilute the original solution by a factor of 2. Start by measuring out 0.5 mL of the 1 mg/mL BSA solution and then add it to a total volume of 1 mL. This will result in a final concentration of 500 µg/mL.

Answer 4

Dilute with the same amount of water (or buffer), e.g. 10 µl BSA at 1 mg / ml + 10 µl water -> 20 µl BSA at 500 µg / ml.

Answer 5

There are 1000ug in a milligram. Therefore here, you have to do a 1 in 2 dilution. So you dilute 1 part stock for every 1 part solvent.