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If the area is doubled while keeping the pressure the same, the thrust on the bottom of the liquid level would also double. This is because thrust is directly proportional to the area in contact with the liquid. Therefore, increasing the area will result in a corresponding increase in the thrust exerted on the bottom.

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How would thrust on the bottom of a liquid level change if area is doubled keeping the pressure same?

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How could thrust in the bottom of the liquid level change if area is doubled keeping the pressure same?

If the area of the bottom of the liquid level is doubled while keeping the pressure constant, the thrust (force exerted by the liquid) would also double. This is because thrust is directly proportional to the area of the bottom of the liquid level acting on the fluid. Therefore, doubling the area would result in double the force or thrust.


How would pressure change if area is doubled keeping the force constant?

Since P = F/A, PA = F So, if area is doubled, pressure is halved.


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