First get moles HCl, then get the grams HCl.
Molarity = moles of solute/Liters of solution
3.8 M HCl = X moles/17.2 Liters
= 65.36 moles HCl
===============so,
65.36 moles HCl (36.458 grams/1 mole HCl)
= 2382.89 grams HCl
======================and,
put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.
To prepare a 10 ml of a 25 M HCl solution, you would need to dilute the 1 M HCl solution by a factor of 25. You will need 0.25 ml of the 1 M HCl solution and 9.75 ml of solvent (usually water) to make a total volume of 10 ml for the 25 M HCl solution.
The answer is 15,039 g hydrogen chloride (HCl).
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
100 M HCl don't exist.
When Dilute HCL is added to water a more diluted solution of HCl is made.
To prepare 1M Tris-HCl from a 10mM solution, you would need to dilute the 10mM solution by a factor of 100. This means you would mix 1 part of the 10mM solution with 99 parts of water to achieve a final concentration of 1M Tris-HCl.
To prepare a 10mM solution of Tris-HCl, you would weigh out the appropriate amount of Tris-HCl powder using a balance and dissolve it in water to make a final volume of solution. For example, to make 1L of 10mM Tris-HCl solution, you would need to dissolve 0.121g of Tris-HCl in 1L of water.
To prepare 1 liter of 0.1N HCl solution from 12N HCl, you would need to dilute the 12N HCl by a factor of 120. To do this, you would add approximately 83.33 mL of 12N HCl to a container and then dilute it with water to reach a final volume of 1 liter. Make sure to mix the solution thoroughly after dilution.
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION
To prepare a 0.2N HCl solution from 1.0N HCl, you can dilute the 1.0N HCl solution by adding 4 parts of water to 1 part of the 1.0N HCl solution. This means combining 1 volume of 1.0N HCl with 4 volumes of water to obtain the desired 0.2N HCl solution.
To prepare a 1.3N HCl solution, you would need to dilute concentrated hydrochloric acid (usually 37% HCl) with water in a specific ratio. Measure out 1.3 moles of HCl in a specific volume and then dilute it to the desired final volume with water. Make sure to handle concentrated HCl with caution and follow proper safety protocols.
To prepare 0.02N HCl solution, you would need to dilute a more concentrated HCl solution with water. Calculate the volume of concentrated HCl needed using the formula C1V1 = C2V2, where C1 is the concentration of the concentrated HCl, V1 is the volume needed, and C2 is the desired concentration (0.02N). Dilute the calculated volume of concentrated HCl with water to reach the desired final volume.
To prepare 10mL of a 25M HCl solution, you would need to dilute the concentrated HCl solution with the appropriate amount of water. For example, to make a 25M solution, you could start with a 10M HCl solution and dilute it appropriately. To determine the specific volume of each solution needed for dilution, you can use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial solution, C2 is the final concentration, and V2 is the final volume.
To prepare a 0.100 M HCl solution from a 1.50 M HCl solution, you need to use the dilution formula, which is M1V1 = M2V2. You would need to use (V_1 = \frac{M_2V_2}{M_1}) to calculate the volume needed. Plugging in the values, you would need to use ( V_1 = \frac{0.100 M \times 2.00 L}{1.50 M} = 0.133 L or 133 mL) of the 1.50 M HCl solution.
To prepare 1M HCl solution from 35% HCl solution, you would need to dilute the 35% HCl with water. Use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial solution, C2 is the final concentration (1M), and V2 is the final volume (1 liter in this case). Calculate the volume of 35% HCl needed to achieve a 1M solution, then add water to make up the total volume to 1 liter.
520 ml of HCl in 480 ml of water=1000ml = 5 N
To prepare a 0.1N HCl solution, you would need to dilute concentrated hydrochloric acid with water in a specific ratio. Measure the required volume of concentrated HCl (37%) based on the formula: M1V1 = M2V2, where M is the molarity and V is the volume. Then, dilute the measured volume of HCl with water to reach the desired final volume while stirring.