10 mg/ml stock solution
To prepare a 10 mm solution, you would dilute the 4 M stock solution. Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (4 M), V1 is the volume of stock solution needed, C2 is the desired final concentration (10 mM), and V2 is the final volume of the solution. Calculate the volume of stock solution needed to achieve the desired concentration, then add solvent (usually water) to reach the final volume.
To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).
You would solve for M1, which represents the molarity of the stock solution. The equation M1V1 = M2V2 is used to calculate the molarity of a stock solution when you know the volume and molarity of a more diluted solution.
This depends on the dilution ratio.
To prepare a 100 ppm stock solution of nickel nitrate in 250 ml, first calculate the mass of nickel nitrate needed. Nickel nitrate (Ni(NO3)2·6H2O) has a molar mass of approximately 290.79 g/mol. For a 100 ppm solution, you need 100 mg of nickel nitrate in 1 liter, so for 250 ml, you would require 25 mg of nickel nitrate. Weigh out 25 mg of nickel nitrate, dissolve it in a small volume of distilled water, and then dilute the solution to a final volume of 250 ml with distilled water in a volumetric flask.
To prepare a 10 mm solution, you would dilute the 4 M stock solution. Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (4 M), V1 is the volume of stock solution needed, C2 is the desired final concentration (10 mM), and V2 is the final volume of the solution. Calculate the volume of stock solution needed to achieve the desired concentration, then add solvent (usually water) to reach the final volume.
(385 mL)(0.766 M NaOH) = (X mL)(4.03 M NaOH)4.03X = 294.91X = 73.2 ml============Take 73.2 mL of stock solution and add ( 385 mL - 73.2 mL = 311.8 mL) 312 mL of water to stock solution.
To prepare a 0.5M glutaraldehyde solution, you would need to dilute a concentrated glutaraldehyde stock solution with the appropriate volume of water or buffer solution. Calculate the volume of stock solution needed based on the desired final volume and concentration, then dilute with the solvent. Finally, mix the solution thoroughly to ensure uniform distribution. Remember to follow safety protocols when working with glutaraldehyde, as it is a hazardous chemical.
To prepare a 0.50 M acetic acid solution, you would need to dilute the 2.5 M stock solution. By using the formula M1V1 = M2V2, you can calculate the volume of the stock solution needed as: (0.5 M)(100.0 mL) = (2.5 M)(V2), where V2 is the volume of the stock solution needed. So, V2 = (0.5 M x 100.0 mL) / 2.5 M = 20.0 mL. Therefore, you would need 20.0 mL of the 2.5 M stock solution to prepare the desired 100.0 mL of 0.50 M acetic acid solution.
To prepare 500 mL of a 0.5 M solution of acetic acid, you would need to take 100 mL of the 2.5 M stock solution and dilute it to 500 mL. This is because the molarity equation (M1V1 = M2V2) can be used to calculate the volume of stock solution needed for dilution.
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
To prepare 1N H2SO4 from 95% H2SO4, you would first need to dilute the 95% H2SO4 with water by adding the appropriate amount of water to achieve the desired concentration. To calculate the volume of 95% H2SO4 needed to make 1N solution, you need to use the formula: (Normality of stock solution) * (Volume of stock solution) = (Normality of diluted solution) * (Volume of diluted solution). Adjust the volumes accordingly to prepare the desired 1N solution.
To prepare 1 L of 15 M NaOH solution, you need to dilute the 6 M stock solution. You would need to take 500 mL of the 6 M NaOH stock solution and add water to bring the total volume up to 1 L. This will give you a final concentration of 15 M.
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).
To prepare 1000 ml of 0.02 M NaCl solution, you would need 40 ml of 5 M NaCl solution, which you can calculate using the formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired concentration, and V2 is the final volume. The dilution factor in this case would be 25, as you are diluting the 5 M solution 25 times to achieve the desired 0.02 M concentration.
To prepare a 6N NaOH solution from a 10N NaOH solution, you would dilute the 10N solution by adding water. Use the dilution formula: C1V1 = C2V2, where C1 is the initial concentration (10N), V1 is the volume of stock solution needed, C2 is the final concentration (6N), and V2 is the final volume of the solution you want to make. Calculate the volume of the 10N solution needed and add water to reach the final desired volume for a 6N NaOH solution.