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What would happen to the rate of a reaction with rate law rate k NO H2 if the concentrations of NO were doubled?

The rate would be four times larger


What would happen to the rate of a reaction with rate law rate kNO2H2 if the concentration of NO were double?

The rate would quadruple (increase by a factor of 4). This is because the rate depends on the SQUARE of the concentration of NO.


What would happen to the rate of a reaction with rate law rate kNO2H2 if the concentration of NO were halved?

In the given rate law, the rate of the reaction is dependent on the concentration of NO and possibly other reactants. If the concentration of NO is halved, the rate of the reaction would decrease proportionally, assuming that NO is a reactant in the rate law. Specifically, if the rate law is of the form rate = k[NO]^n[other species], the rate would be affected by the new concentration of NO, resulting in a reduced reaction rate. The exact impact on the rate would depend on the order of the reaction with respect to NO.


What measurements would need to be taken to calculate the rate of diffusion of a gas?

To calculate the rate of diffusion of a gas, you would need to measure the concentration gradient, which involves determining the concentration of the gas at two different points over a specific distance. Additionally, the temperature and pressure of the gas are important, as they influence the kinetic energy and behavior of gas molecules. Finally, the molecular weight of the gas is necessary, as it affects the diffusion rate according to Graham's law.


What would happen to the rate of a reaction with rate law rate k NO2H2 if NO were halved?

In the rate law given as rate = k[NO2][H2], the concentration of NO does not appear, so the rate of the reaction is independent of its concentration. Therefore, if the concentration of NO were halved, it would have no effect on the rate of the reaction. The reaction rate would remain unchanged as long as the concentrations of NO2 and H2 remain constant.

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What would happen to the rate of a reaction with rate law rate k NO H2 if the concentrations of NO were doubled?

The rate would be four times larger


What would happen to the rate of a reaction with rate law rate k NO2H2 if the concentration of NO were doubled?

The rate would be one-fourth. Correct on Apex.


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What would happen to the rate of a reaction with rate law rate kno2h2 if the no were doubled?

the rate would be four times larger. apex


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