How you have find the number of total isomers of c5h10?

Answer 1

DOUBLE BOND EQUIVALENTS or INDEX NUMBER:

It is a numerical value on the basis of which we can have an idea about the different type of equivalent structures we can have for a given formula.

Knowing the DBE the problems on structural isomerism can be more easily solved.

Mathematically,

DBE= {( n(v-2))/2}+1

where n is the number of atoms

v is the valency of the atom.

Eg 1):

Consider C4H6

DBE={4(4-2)/2+6(1-2)/2}+1

={(8-6)/2}+1

=2

This implies that the molecule may contain,

1)two double bonds or one triple bond.

2)one ring and one double bond.

3)two rings.

Thus by knowing the DBE total number of structural isomers can be formulated.

Eg 2):

Consider C3H6O

DBE={3(4-2)/2+6(1-2)/2+1(2-2)/2}+1

=1

So the isomers may contain either a double bond or a ring.

I hope this is helpful!

Answer 2

The number of total isomers of C5H10 can be found using the formula 2^n, where n is the number of unique isomers possible for that molecular formula. For C5H10, there are 3 unique isomers (pentane, 2-methylbutane, and cyclopentane), so the total number of isomers would be 2^3 = 8.