Chemists observe the ratio with which a given element combines with other elements. That is how all the conclusions about oxidation states are derived. Since we also have data on the atomic weight of elements, we can weigh a given sample and know how many moles it contains. If one mole of rubidium combines with one mole of chlorine, we can conclude that rubidium has an oxidation state of 1, combining evenly with chlorine, which has an oxidation state of minus one. Millions and millions of different chemical reactions have been observed, and all this observation has been analysed to determine what the elements are actually doing.
It is simply known as rubidium nitrite.
Rubidium typically forms only one oxidation state, which is +1. In this form, it loses one electron to achieve a stable electron configuration. Rubidium does not commonly exhibit other oxidation states due to its position in the alkali metal group on the periodic table.
O = -2 oxidation state H = +1 oxidation state
The oxidation state of F in HOF (hydrogen monofluoride) is -1. Hydrogen is typically assigned an oxidation state of +1, leaving the fluorine with an oxidation state of -1.
Oxidation state of Oxygen in:Peroxides is -1Superoxides is - 1/2
1+ (it is in group 1)
It is simply known as rubidium nitrite.
0 in elemental form and +1 in its compounds
Rubidium typically forms only one oxidation state, which is +1. In this form, it loses one electron to achieve a stable electron configuration. Rubidium does not commonly exhibit other oxidation states due to its position in the alkali metal group on the periodic table.
When rubidium, an alkali metal, group 1, reacts it loses one electron.
It's just Rubidium Sulfate. The name rubidium sulfate (sulfate is SO3)assumes that people can figure out the chemical formula based on the oxidation numbers of rubidium (+1) and sulfate (-2) and crisscrossing to get a net oxidation number of zero.
The chemical formula for the compound formed between rubidium and sulfur is Rb2S. Rubidium is in Group 1 of the periodic table with a +1 oxidation state, while sulfur is in Group 16 with a -2 oxidation state, so they combine in a 1:1 ratio to form Rb2S.
The oxidation state of chloride (Cl) is -1. As a halogen, chloride is usually found with an oxidation state of -1 in most compounds.
O = -2 oxidation state H = +1 oxidation state
This oxidation state is 1.
The oxidation state of F in HOF (hydrogen monofluoride) is -1. Hydrogen is typically assigned an oxidation state of +1, leaving the fluorine with an oxidation state of -1.
This answer is -1.To find this answer:Oxygen has an oxidation number of -2.Hydrogen has an oxidation number of +1, and there are 3 of themyou want to get the oxidation numbers to add up to 0, so it would be neutral.-2 + 3(+1) = +1Now, to get this to equal zero, it means that N has to be -1.