NaCl
The products of a chemical change are the substances formed as a result of the reaction, while the reactants are the starting substances that undergo the change. In a chemical equation, reactants are on the left side and products are on the right side.
The result of a reaction/reactants. NaOH and HCl are reactants here.NaOH + HCl --> NaCl + H2ONaCl, a salt is a product of this reaction and water ( H2O ), though you are just adding more water to the solution, is also a product of this reaction.
One possible reaction is 2 NaOH + H3PO4 = Na2HPO4 + 2 H2O.
A balanced chemical equation must observe the law of conservation. There must always be the same number of the atom within the reactants and within the products. For example, in the reaction between NaOH and HCl: NaOH + HCl --> NaCl + H2O On both sides of the equation, I have 2 hydrogen atoms, 1 chlorine atom and 1 sodium atom.
The reactants are hydrochloric acid (HCl) and sodium hydroxide (NaOH).
The reactants in the reaction are hydrochloric acid (HCl) and sodium hydroxide (NaOH).
The reactants are NaCl and H2O. A becks: HCl NaOH
NaCl
The reactants are on the LEFT side of the arrow; the products are on the RIGHT side of the arrow. Note: "Reactants"=what is reacting; what you are starting with. "Products"=something you create. Thus, hydrochloric acid and sodium hydroxide are the reactants in this equation.
An acid-base reaction
NaOH and HCl are the reactants; water and ammonium chloride are the products.
The reaction is: NaOH + HCl = NaCl + H2O
When NaOH (sodium hydroxide) reacts with HCl (hydrochloric acid), they undergo a neutralization reaction to produce water (H2O) and sodium chloride (NaCl) salt. The balanced chemical equation for this reaction is: NaOH + HCl -> NaCl + H2O.
Mixing hydrochloric acid (HCI) with sodium hydroxide (NaOH) in water (H2O) will result in a neutralization reaction, producing sodium chloride (NaCl) and water. The balanced chemical equation for this reaction is: HCl + NaOH → NaCl + H2O.
NaCl and H2O
NaCl doesn't undergo a chemical reaction with NaOH, so you wouldn't be able to tell.