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Convert 6.5kcal to Joules?
1 cal ~ 4.18 J <-- known 6.5 kcal = 6500 cal = 4.18 [J / cal] * 6500 [cal] = 27170 [J] or 2.72e+4 [J]
If an endothermic process absorbs 263 Joules how many kilo-calories are absorbed?
To convert Joules to kilocalories, divide the amount of energy in Joules by 4184 (the conversion factor between Joules and kilocalories). Thus, 263 Joules is equivalent to approximately 0.063 kcal.
How much heat in joules is needed to raise the temperature of 1.0 L of water from 0 C to 100 C?
100*1*4,186.8= 418,680
How many meters in 2.6 miles?
Answer: 2.6 mi. = 4184.294 m
Time required to raise 1 degree centigrade in 1 liter of water?
To determine the time this will take, you need to know the rate at which heat is being added to the system. The specific heat capacity of a substance is the amount of energy required to raise the temperature of one gram of a substance one degree centigrade. For water at 25oC, the specific heat capacity is 4.184 J*g-1*oC-1. That is, if you have one gram of water, you must add 4.184 Joules of energy (heat) to raise the temperature one one degree centigrade. The time it takes for the temperature increase to happen depends on how quickly you add the 4.184 J. Adding heat at a rate of 1 Joule/second (which is equivalent to 1 Watt), it is easy to see that it will take 4.814 seconds to raise the temperature of the gram of water one degree centigrade. The first step to solving your problem, then, is to make your data units compatible with your known constants. We need to convert volume to mass. We do this by means of density. The density of liquid water at standard temperature and pressure is 1g/mL. 1L H2O *1000mL/1L *1g H2O/mL H2O= 1000g H2O Then, to find the amount of energy required to change the temperature of the mass, we use the specific heat. 1000g H2O *4.184J/(g*K)= 4184 J/oC Note the units on this last value. They give the amount of energy needed required per degree centigrade of change in the temperature. That is, it requires 4814J to change the temperature of 1000g H2O one degree centigrade. Given the time rate of heat transfer into the system, you can find the time required to make the change. If, for instance, your heat exchange rate is 5 Watts (J/s), you would have 4184 J/oC * 1 second/5 Joules = 836.8 s/oC This value allows you to calculate the time required for any change in temperature simply by multiplying the number of degrees centigrade temperature change. For one degree, we find 836.8 s/oC *1oC = 836.8s
If the kcal is 185 what is it in calories?
184,999.99989344 in 185 kcals 1 joule = 0.239005736 calories 1 kilocalorie (kcal) = 4184 joules 185kl x 4184 Joules x 0.239005736 calories = 184,999.99989344
What is the unit of energy equaled to 1000 kilocalories?
1 kilocalorie (kcal) is equal to 4184 joules. Therefore, 1000 kilocalories would be equal to 4184000 joules.
What is the unit if he energy used in physical science and feed science?
A Joule is the SI unit of energy. It is equal to 1 Newton force, multiplied by 1 meter.The calorie is a heat energy unit. Equal to approx 4.184 Joules. In food Calories, is actually equivalent to a kilocalorie (1000 calories, or 4184 Joules).
Convert 6.5kcal to Joules?
1 cal ~ 4.18 J <-- known 6.5 kcal = 6500 cal = 4.18 [J / cal] * 6500 [cal] = 27170 [J] or 2.72e+4 [J]
4 calories contains how many watts?
16,736 since 1calorie= 4184 joules.
What is used to measure enegry?
Energy is measured in Joules or calories. One calorie is equal to 4.184 Joules, not to be confused with kilocalories or Calories (with a capital C) which, in concordance with the metric system is equal to 4184 Joules.
If an endothermic process absorbs 263 Joules how many kilo-calories are absorbed?
To convert Joules to kilocalories, divide the amount of energy in Joules by 4184 (the conversion factor between Joules and kilocalories). Thus, 263 Joules is equivalent to approximately 0.063 kcal.
What is the change in thermal energy of the water in a pond with a mass of 1000 kg and a specififc heat of 4184 kg if the water cools by 1 degree c?
The change in thermal energy (Q) of the water can be calculated using the formula Q = mcΔT, where m is the mass, c is the specific heat, and ΔT is the change in temperature. For the water in the pond, Q = 1000 kg × 4184 J/(kg·°C) × (-1 °C) = -4,184,000 J. This indicates that the thermal energy of the water decreases by 4,184,000 joules as it cools by 1 degree Celsius.
How many kilocaclories of heat does the operation of a 1190 watt hair dryer produces each second?
Watts means joules per second. The device uses 1190 joules of energy every second; most of that will be converted to heat. It is best to use SI units most of the time; in this case, joules rather than calories for energy. However, if you want to convert that, 1 calorie = 4.184 joules; thus, you can divide the number of joules by 4.184 to convert it to calories.
What is a person's maximum number of METS called?
A person's maximum number of METS is also called kcal level. Kcal is also known as kilocalorie. 1 Kilocalorie is equal to 4184 joules.
What is a kilocalery?
A kilocalorie is one food calorie. A standard calorie is a unit of energy equal to 4.184 joules. This is a very small amount of energy, so when we're talking about the amount of energy in food, we use kilocalories, which is equal to 1000 standard calories. When we're talking about food, we always say that it has so many calories, but forget to note that we're talking about food calories, which makes it somewhat confusing. 1 standard calorie= 4.184 joules 1000 standard calories= 1 kilocalorie= 1 food calorie= 4184 joules If a piece of food has 80 (food) calories, then it has 80 kilocalories, or 80,000 standard calories.
How many calories required to raise temperature of 1 liter of water 1 degree centigrade?
Well, let's see. Water at room temperature has a heat capacity of 4.18 J/g-C, and water also has a density of 1g/mL. If there's one litre of water, there's 1000 g of water. If the change in temperature is 1 C, and there are 1000 g of water, and specific heat capacity's 4.18... Q = mcT Q = (1000g)(4.18J/g-C)(1 C) Q = 4180 J So you need 4180 J of heat. *************************************** The definition of one calorie is as stated in the question. One calorie is equivalent to 4.18 Joules. Not sure where the maths went wrong but just so you know.
