Well, isn't that just a happy little question! To find the percentage strength of the solution, we need to calculate the amount of chemical in the solution first. Since we have 4kg of chemical in 200 liters of solution, the percentage strength would be 4kg divided by 200 liters, then multiplied by 100 to get the percentage. Happy calculating!
To prepare a 0.2 (20%) chemical solution in 90 liters of water, you need to calculate the amount of the dry chemical required. A 20% solution means that 20% of the total solution is the chemical. Since 90 liters of water is being used, the total volume of the solution will be approximately 90 liters (assuming the volume of the chemical is negligible). Therefore, 0.2 x 90 L = 18 kg of dry chemical must be added to the water to achieve the desired concentration.
Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========
To find the strength of the solution, you can calculate the concentration in grams per liter (g/L). Since 800 milliliters is 0.8 liters, the concentration of dextrose is ( \frac{120 \text{ grams}}{0.8 \text{ L}} = 150 \text{ g/L} ). Therefore, the strength of the solution is 150 g/L.
To prepare a 2% solution in 3 liters, you would need 60 grams of the drug. This is calculated by multiplying the volume (3 liters) by the percentage (2%) and converting the result to grams. 3 liters x 2% = 60 grams.
To find out how many liters of a 0.1 M solution are needed to obtain 0.5 moles, you can use the formula: [ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} ] Rearranging this gives: [ \text{liters of solution} = \frac{\text{moles of solute}}{\text{Molarity (M)}} ] Substituting in the values: [ \text{liters of solution} = \frac{0.5 \text{ moles}}{0.1 \text{ M}} = 5 \text{ liters} ] Therefore, you would need 5 liters of a 0.1 M solution to obtain 0.5 moles.
To prepare a 0.2 (20%) chemical solution in 90 liters of water, you need to calculate the amount of the dry chemical required. A 20% solution means that 20% of the total solution is the chemical. Since 90 liters of water is being used, the total volume of the solution will be approximately 90 liters (assuming the volume of the chemical is negligible). Therefore, 0.2 x 90 L = 18 kg of dry chemical must be added to the water to achieve the desired concentration.
0.1125% of polymer solution.
Concentration of a solution is recorded in molarity (M). Molarity is the moles of solute divided my liters of solution. So to find the concentration of a solution, calculate the number of moles of the solute (the chemical being dissolved) and measure the number of liters of the solution (the water), then divide them.
4.5%
The relationship between percentage and molarity in a solution is that percentage concentration is a measure of the amount of solute in a given amount of solution, expressed as a percentage. Molarity, on the other hand, is a measure of the concentration of a solution in terms of the number of moles of solute per liter of solution. The two are related through the formula: percentage concentration (molarity x molar mass of solute) / (volume of solution in liters).
You would need 6.15 kg of calcium hypochlorite powder at 65% strength to make 200 liters of 2% hypochlorite solution.
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.
Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========
10 liters.
4.5 litres of a 30% solution to the appropriate quantity of the 90% solution.
11.8 % steps are: 56 / 473.2 ( how much Liters in a 1pint )* 100= 11.8