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Heat gained by one object has to equal the heat lost by the other object. The final temperature of the two objects will be the same.

Object 1:

mass1 = 50 g

initial T1 = 20 oC

Cg = 2 J/degree/gram

final T1 = Tf

Change in temperature = Tf - T1

Q = Cg x change in T x mass

= 2 x ( Tf - T1 ) x 50

Water:

Mass = 200 g

Cg = 4.18 J/ degree/ gram

Change in T = Tf - 40

Q = 4.18 x (Tf - 40) x 200

4.18 x (Tf - 40) x 200 = -(2 x ( Tf - 20 ) x 50)

Tf = 37.9 oC

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