say ramp angle = 30deg from horizontal, launch velocity = 10 m/s, launch point is 1m above floor
break launch velocity vector into horizontal and vertical components
horizontal = cos 30 * 10 = 8.66 m/s, vertical = sin 30 * 10 = 0.5*10=5 m/s
the horizontal component is constant so if you multiply the time the ball spends going up and down by 8.66 this represents horizontal travel
take g as -10 m/s^2, u=5, v=0 ,s=?, t=?
find height reached and time taken, t=v-u/g = 0.5secs, s=(u*t)+((g*t^2)/2)=1.25m, now add how long to fall 1.25 m+ original height (1m) = 2.25m
remember g is now +10 m/s^2, u=0, s=2.25m ,t=?
then t= sq root(s*2/10)=0.671secs(falling), add to 0.5 secs(rising) = 1.171secs, multiply by 8.66m/s then horizontal travel = 10.14 metres
when a ball is dropped it hits the floor and the ball is flattened. That creates energy. The only way the ball can release the energy is bouncing back up. But the ball starts to lose its height and the ball eventually loses its energy and comes to a stop.
A ball bounces because it's shape changes when it hits another object, then it returns to it's original form, pushing itself away from the object. When a ball is cold it's molecules don't move as much, so the shape changes less when it hits an object.
newton's laws of motion apply to tennis because of the 3 law of motion. For every action there is an equal and opposite reaction. So when the ball hits the racket the force from the racket makes the ball move forward.Also the second law applies because the law is an object in motion will tend to stay in motion until an outside force acts upon it. So when the player hits the ball gravity is putting a force on the ball which brings the ball to the ground. If gravity didn't exist then the ball would go on forever.
A classical cannon ball doesnt have enough speed, but a modern heavy artillery shell will cause enough wind to blow bystanders away, and thus possibly kill them.
The ball stops bouncing due to a loss of energy through various forms such as heat, sound, and deformation of the ball. As the ball bounces repeatedly, these energy losses accumulate, causing the ball to eventually come to a stop.
No.
When the ball hits the floor of your opponents side of the court.
Yes, they are required to hit the ball before it hits the floor a second time ... no matter how may walls it hits.
No, it is simply a ground ball and is in play.
i think its compression and ... sorry i don't know the other one
When serving team hits the ball and returning team cannot return in three tries or when ball hits the floor. Serving team hits the ball and it goes out of bounds point for other side.
It is called an Ace.
If the opponent has established position out of bounds (at least one foot on the floor) then the ball would still be yours. If the opponent is in the air and has not established position out of bounds the ball is still live.
This call is used when the ball hits the floor on one side of the court, so the referee points it at the floor, signifying the ball landed on that side and was in bounds.
This is called an ace.
Landing foot? Or grounded foot.
The team that hit the ball over will get a point.