The brown eyed woman is heterozygous genotype with a dominance of brown eyes, usually represented Bb -- capital 'B' as the brown gene and lower case 'b' as the blue gene. She has the possibility of passing both blue and brown eyes onto her offspring, however blue eyes only have a 25% chance of being expressed in the offspring The brown eyed woman is heterozygous genotype with a dominance of brown eyes, usually represented Bb -- capital 'B' as the brown gene and lower case 'b' as the blue gene. She has the possibility of passing both blue and brown eyes onto her offspring, however blue eyes only have a 25% chance of being expressed in the offspring
The woman would have genotype AO (IAIA) for blood type A, the man would have genotype BO (IBIB) for blood type B, and their child with blood type O would have genotype OO (ii). The child inherited one O allele from each parent.
If an AC genotype man and an AS genotype woman marry, each of their children has a 25% chance of being born with a sickle cell disease (SS genotype), a 50% chance of being a carrier like their parents (AS genotype), and a 25% chance of having a normal genotype (AA).
The woman would have blood type A. A genotype of IA indicates the presence of the A antigen on red blood cells.
Assuming the dystonia is hereditary and is a recessive gene which will be called "d" for simplicity, that means the man must be "dd" and the woman is "Dd". This is the only way they could have a child who is "dd" like the father, but not the mother.
I don't know what your scientific terms mean, but I can tell you that I am a blue eyed female (my father was brown eyed/my mother had hazel eyes). The father of my two children is brown eyed. Both of my children have blue eyes.
The mother's genotype is rr. The daughter would inherit one recessive allele from her mother because her mother has only recessive alleles. Because the daughter is green eyed, she would inherit a dominant allele from her father. The brown-eyed daughter's genotype would be Rr.
Yes.
The plural of "woman" is "women". "Womans" is not a plural form of the word "woman".
The woman would have genotype AO (IAIA) for blood type A, the man would have genotype BO (IBIB) for blood type B, and their child with blood type O would have genotype OO (ii). The child inherited one O allele from each parent.
The genotype of the man is A negative/O negative inheriting the A neg from his mother and O negative from his father. [Father's genotype is B positive/O negative. Mother's genotype is B positive/A negative.]
A woman with type A blood may have genotype AO or AA. The heterozygous type is AO.
A womans name.
Yes, if the mother's genotype is BO, she may pass the O allele on to the child and it will be type O.
She is a carrier of hemophilia but does not have the condition
It ends with i, WOMANS NAME
If an AC genotype man and an AS genotype woman marry, each of their children has a 25% chance of being born with a sickle cell disease (SS genotype), a 50% chance of being a carrier like their parents (AS genotype), and a 25% chance of having a normal genotype (AA).
The woman would have blood type A. A genotype of IA indicates the presence of the A antigen on red blood cells.