It depends on which trait is dominant and whether the silver-blue mink is homozygous or heterozygous.
In this case, it doesn't matter what the genotype of the other parent is since BB is homozygous dominant (assuming this is the only gene that affects coat colour of course). All of the BB parent's offspring will PHENOTYPICALLY be brown-coated. They may be heterozygous though (Bb) depending on genotype of the second parent. So the PHENOTYPIC probability of a brown coat is 100% The genotypic probability of a homozygous genotype depends on the second parent.
To calculate the probability of a homozygous dominant (BB) offspring from a cross between two rabbits, we need to consider their genotypes. If both parents are heterozygous (Bb), the possible offspring genotypes would be BB, Bb, Bb, and bb, giving a probability of 1 out of 4, or 25%, for a homozygous dominant (BB) offspring. If one parent is homozygous dominant (BB) and the other is heterozygous (Bb), the probability of BB offspring is 1 out of 2, or 50%.
Rr
It would depend on the brunette's genotype. If they are heterozygous for that trait, then the offspring could be any combination of blonde hair, brown hair, blue eyes, or brown eyes. If the brunette is homozygous dominant, then it's 100% sure the offspring will have a phenotype the same as the brunette.
a brown horse i just did this in school a few weeks ago
75% or 3/4. The two F1 (offspring) mice have a genotype Bb, and express the dominant (brown) trait. When they mate, 1/4 will be BB (homozygous dominant - brown), 2/4 will be Bb (heterozygous - brown), and 1/4 will be bb (homozygous recessive - white).
The pair of alleles were homologous because they were the same.
The Punnett square for crossing two heterozygous dogs (Bb x Bb) would result in a 25% chance of offspring with homozygous dominant black fur (BB), a 50% chance of offspring with heterozygous black fur (Bb), and a 25% chance of offspring with homozygous recessive brown fur (bb).
my doe is black and my buck is brown. They have 3 brown offspring and 2 black. Actually one bunny is brown with black. So i can say that it is 50-50
In this case, it doesn't matter what the genotype of the other parent is since BB is homozygous dominant (assuming this is the only gene that affects coat colour of course). All of the BB parent's offspring will PHENOTYPICALLY be brown-coated. They may be heterozygous though (Bb) depending on genotype of the second parent. So the PHENOTYPIC probability of a brown coat is 100% The genotypic probability of a homozygous genotype depends on the second parent.
all brown the chances of brown eyes both parents have to have blueeyes for blue eyes to become dominant but its still possible no matter what for blue or brown
Rr
If both parents are black-haired guinea pigs and the black coat color is dominant, they could either be homozygous (BB) or heterozygous (Bb) for the black coat gene. If both are heterozygous (Bb), the offspring ratio would typically be 25% homozygous black (BB), 50% heterozygous black (Bb), and 25% brown (bb). Therefore, among the 20 offspring, we would expect around 15 to be black (BB or Bb) and about 5 to be brown (bb) if the parents are Bb. If both parents are homozygous (BB), all offspring would be black.
You can use a Punnet Square to figure it out. For example, if gray elephants dominate over brown elephants, and you cross 1 homozygous gray elephant (GG) and one homozygous brown elephant (gg), the Punnet square predicts that the offspring will all be heterozygous Gg. They will all be gray, however, because gray dominates over brown.
Half of the offspring, or 100 rabbits, would be expected to be white when offspring from a heterozygous brown rabbit and a white rabbit are produced. This is due to the dominant-recessive inheritance pattern where brown is dominant and white is recessive.
heterzygous with brown leaves
White fur color is recessive and brown is dominant. The white mouse has a genotype of bb and the brown mouse has a genotype of BB. All offspring would be heterozygous with a genotype of BB and brown fur.