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Assuming that no net external forces are taking place, such as friction or air resistant, the only force acting upon the falling rock would be gravity. Using one of the kinematic equations, we can solve for the final velocity of the rock:

v(final) = v(initial) + at

We can substitute 0 for "v(initial)" since the rock is starting from rest. We can also substitute 9.81 meters per second squared for "a", which is the gravitational acceleration on Earth. Finally, we can substitute 9 seconds for "t". This gives us:

v(final) = 0 + (9.81)(9)

v(final) = 88.29 meters per second.

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