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No. No, i believe that the person would not know that they were exposed to choroform, but do indeed remember what had happened had they woken up.

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16y ago

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Do you know if you are given chloroform?

No you can not know about that. It is a anesthetic.


What is the number of moles of chloroform (CHCl3) in 215 g of chloroform.?

To find the number of moles of chloroform in 215 g, you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform (CHCl3) is approximately 119.38 g/mol. Therefore, 215 g of chloroform is equal to 1.80 moles.


How many moles in 59.1 g of chloroform?

molar mass of CHCl3 is119.5gmol-1. so there are 0.49 moles.


What is the molecular mass of chloroform if .0275 mol weighs 3.28 g?

(3.28 g of chloroform/.0275moles of chloro)= 119 g of chloroform. Just take the weights in grams and divide it by number of moles. Hope it helps!


How many moles are in 59.1 g of chloroform?

To find the number of moles in 59.1 g of chloroform (CHCl3), you need to divide the given mass by the molar mass of chloroform. The molar mass of chloroform is approximately 119.38 g/mol. Dividing 59.1 g by 119.38 g/mol gives approximately 0.495 moles of chloroform.


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If the pressure of gaseous chloroform in a flask is 195 mm Hg at 25C and its density is 1.25 gL what is the molar mass of chloroform?

Using the ideal gas law, we can determine that the molar mass of chloroform is approximately 119 g/mol. Given the pressure, temperature, and density of chloroform, you can calculate the molar mass using the formula: (pressure x molar mass) / (gas constant x temperature) = density. Solving for molar mass gives approximately 119 g/mol.


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How do you convert chloroform into ethyne?

Chloroform will convert to ethylene by heating the former with silver powder. Chloroform is represented by the chemical formula CHCl3. Ethyne also known as acetylene is represented by the chemical formula C2H2. The silver powder acts as reducing agent in the given conversion, it reduces carbon and itself gets oxidized. The reaction for conversion is as follows: 2CHCl3 + 6Ag --> C2H2 + 6AgCl. In the given reaction, Ag is silver and AgCl is silver chloride.