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To provide an accurate answer, I would need the specific parental genotypes involved in the cross. However, if we assume a simple Mendelian cross between two heterozygous parents (e.g., Aa x Aa), the expected genotypes of the offspring would be: AA, Aa, Aa, and aa. This would yield 1 AA, 2 Aa, and 1 aa, resulting in a total of four offspring with the genotypic ratio of 1:2:1.

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Suppose two white flowered pea plants are crossed and produce 1000 offspring how many of those offspring would you expect to have white flowers?

If both parent plants are white-flowered, then all of the 1000 offspring would be expected to have white flowers. This is because the white flower trait is a result of a homozygous genotype, and both parents would pass on the white flower allele to their offspring.


Which statement best predicts the results of the cross MmDdPp x mmddpp assuming that all three genes are linked?

If all three genes are physically linked on the same chromosome, we would expect to see higher frequencies of parental genotypes (MmDdPp and mmddpp) in the offspring due to the phenomenon of genetic linkage. Recombinant genotypes (Mmddpp and mmDdPp) would be less frequent, as crossing over events between the linked genes would be less likely to occur.


If you performed the Drosophila cross LL x ll what phenotypic ratio would you expect among the offspring?

You would expect a 1:1 ratio of offspring with a long body (LL) to offspring with a short body (ll) due to the incomplete dominance of the gene for body length in Drosophila.


What kind of phenotype ratio would you expect from a mono-hybrid cross?

possible mendelian ratios for monohybrid cross genotype is 1:2:1 and phenotype is 3:1


What ratio would you expect in a two factor cross if both parents are heterozygous?

In a two-factor cross where both parents are heterozygous for two traits (e.g., AaBb x AaBb), you would expect a phenotypic ratio of 9:3:3:1 in the offspring. This ratio represents the combinations of the dominant and recessive traits for both factors. The 9 represents the offspring with both dominant traits, while the 3s represent the combinations with one dominant and one recessive trait, and the 1 represents the offspring with both recessive traits.

Related Questions

If dad has freckles and is homozygous and mom has freckles and is heterozygous what phenotypes and genotypes can you expect their offspring?

Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.


Suppose two white flowered pea plants are crossed and produce 1000 offspring how many of those offspring would you expect to have white flowers?

If both parent plants are white-flowered, then all of the 1000 offspring would be expected to have white flowers. This is because the white flower trait is a result of a homozygous genotype, and both parents would pass on the white flower allele to their offspring.


What would you expect if you breed or mate 2 different true breeding stocks of plants?

If one trait is dominant over the other, then you would expect all of the offspring to have the dominant trait.


How do geneticists normally tell whether an organism exhibiting a dominant phenotype is homozygous or heterozygous?

They perform a test cross. A test cross takes the unknown genotype and crosses it with a known homozygous recessive. If the F1 generation is all dominant, then they know the organism was a homozygous recessive. If recessive offspring appear, then the organism was a heterozygote. As an example, consider a gene with two alleles, A and a, with Adominant. Now consider the test cross. The unknown genotype can only be one of two possibilities: AA (homozgous dominant) Aa (heterozygous) In a test cross,the unknown genotype is crossed with a known homozygous recessive. Since there are only two possible unknown genotypes, there can be only two possible results. First, consider the case of the unknown genotype being a homozygous dominant. The cross looks like this: AA X aa Remember that a homozygote for an allele can only produce one kind of gamete. In this case the homozygous dominant can only produce gametes with the allele A in them, while the homozygous recessive can only produce gametes with the recessive allele a in them. This means the F1 offspring can only be ONE genotype; Aa. Therefore, all of the offspring would have the dominant phenotype. Now consider the other possible cross, where the unknown genotype is heterozygous: AaX aa Remember that a heterozygote can produce two types of gametes. In this case, the unknown would produce gametes with the dominant allele A or the recessive allele a. The homozygous recessive would still only produce one kind gamete, with the recessive a allele. Therefore, we expect to see only two genotypes in the F1, Aa and aa, in equal proportions. In either case, only one test cross is needed to tell one immediately the nature of the unknown genotype. If all of the F1 are of the dominant phenotype, then the unknown genotype must be homozygous dominant; if a mixture of phenotypes appears in equal proportion, then the unknown genotype must be a heterozygote.


Which statement best predicts the results of the cross MmDdPp x mmddpp assuming that all three genes are linked?

If all three genes are physically linked on the same chromosome, we would expect to see higher frequencies of parental genotypes (MmDdPp and mmddpp) in the offspring due to the phenomenon of genetic linkage. Recombinant genotypes (Mmddpp and mmDdPp) would be less frequent, as crossing over events between the linked genes would be less likely to occur.


What would you expect if you breed or Mate two different true breeding stocks of plants?

If one trait is dominant over the other, then the resulting F1 generation would be expected to have the heterozygous genotype and dominant phenotype.


If you performed the Drosophila cross LL x ll what phenotypic ratio would you expect among the offspring?

You would expect a 1:1 ratio of offspring with a long body (LL) to offspring with a short body (ll) due to the incomplete dominance of the gene for body length in Drosophila.


If 50 DDdd pairs of parrots mate and each pair has 2 offspring how many of the 100 offspring would you expect of be Dd?

c


What can you expect if your sheep impregnates a goat?

A stillborn offspring, the babies of a goat and sheep cross are not able to survive and are stillborn.


In fruit flies gray body color is dominant over black body color How many fruit flies would you expect to have black bodies as of if they had produced 200 offspring?

If black body color is recessive and gray is dominant, we can assume that the black body color is represented by the genotype "bb". Given that gray is dominant, individuals with gray bodies could be either "GG" or "Gg". Thus, for black body color to appear in offspring from two gray-bodied flies, both parents would need to be carriers of the black body allele (each "Gg" or "gg"). Therefore, if both parents are carriers, the expected ratio of black-bodied offspring would be 25% (1/4). In a sample size of 200 offspring, we would expect around 50 flies to have black bodies.


Can a Suriname breed with an Amazon Basin Emerald Tree Boa And what would you expect from the offspring?

These two snakes are of the same species, but are from different areas of the country and also look different. There is no real husbandry information for breeding the two, so it is possible that past attempts have been failures.


Suppose that a gray fruit fly heterozygous for the alleles for body color is crossed with one that has a black body What percentage of the offspring would you expect to have black bodies?

You would expect 50% of the offspring to have black bodies. This is because the offspring will inherit one allele for black body color from the black parent, and one allele for gray body color from the heterozygous gray parent. The black allele is dominant over the gray allele.