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What else can I help you with?
How can you identify if a new substance is made?
You would use trend of the periodic table to pinpoint the group or period of the substance. Then you would use group/period characteristics. If you can not find an element that matches, you will have to repeat the process which you created the element(if you created it). If you found the element then search around for more and team-up with a renowned chemist and prove it. ***It could take a few years to a coule decades to prove it***
Is roentgenium a metal?
Roentgenium (atomic number 111) - Rg is expected to be a transition metal, although sufficient tests haven't been conducted to prove this. It is at the bottom of the transition metals on the Periodic Table and in the Copper family. The synthetic element next to it (Copernicium) has been confirmed as a transition metal.
What kind of experiment would prove that fire is not an element?
You could demonstrate that fire is not an element by capturing it in a container and showing that it can be extinguished, or by isolating the various components of fire (such as heat, fuel, and oxygen) and showing that fire cannot exist without them. This would illustrate that fire is a phenomenon resulting from a chemical reaction, not a fundamental element.
How can you prove that in carbon there is no salt?
In (chemistry) and biology, Carbon (C) is an element, and salt(s) are always molecular compounds. For example, table salt molecular formula is NaCl = sodium + chlorine.
How can you prove a substance is an element?
a little research should help youlink to followhttp://chemistry.about.com/library/weekly/blgroups.htmhope this helps!Finding out the substance in an element is easy. All you have to do is look it up on the periodic table.
Prove that the order of an element of a group of finite order is a divisor of the order of the group?
Let ( G ) be a finite group with order ( |G| ), and let ( g \in G ) be an element of finite order ( n ). The order of ( g ), denoted ( |g| ), is the smallest positive integer such that ( g^k = e ) for some integer ( k ), where ( e ) is the identity element. The subgroup generated by ( g ), denoted ( \langle g \rangle ), has order ( |g| = n ). By Lagrange's theorem, the order of any subgroup divides the order of the group, thus ( |g| ) divides ( |G| ).
Prove that a group of order three is abelian?
By LaGrange's Thm., the order of an element of a group must divide the order of the group. Since 3 is prime, up to isomorphism, the only group of order three is {1,x,x^2} where x^3=1. Note that this is a finite cyclic group. Since all cyclic groups are abelian, because they can be modeled by addition mod an integer, the group of order 3 is abelian.
How do you prove that order of a group G is finite only if G is finite and vice versa?
(1). G is is finite implies o(G) is finite.Let G be a finite group of order n and let e be the identity element in G. Then the elements of G may be written as e, g1, g2, ... gn-1. We prove that the order of each element is finite, thereby proving that G is finite implies that each element in G has finite order. Let gkbe an element in G which does not have a finite order. Since (gk)r is in G for each value of r = 0, 1, 2, ... then we conclude that we may find p, q positive integers such that (gk)p = (gk)q . Without loss of generality we may assume that p> q. Hence(gk)p-q = e. Thus p - q is the order of gk in G and is finite.(2). o(G) is finite implies G is finite.This follows from the definition of order of a group, that is, the order of a group is the number of members which the underlying set contains. In defining the order we are hence assuming that G is finite. Otherwise we cannot speak about quantity.Hope that this helps.
Prove that a group of order 5 must be cyclic?
There's a theorem to the effect that every group of prime order is cyclic. Since 5 is prime, the assertion in the question follows from the said theorem.
How do we prove that a finite group G of order p prime is cyclic using Lagrange?
Lagrange theorem states that the order of any subgroup of a group G must divide order of the group G. If order p of the group G is prime the only divisors are 1 and p, therefore the only subgroups of G are {e} and G itself. Take any a not equal e. Then the set of all integer powers of a is by definition a cyclic subgroup of G, but the only subgroup of G with more then 1 element is G itself, therefore G is cyclic. QED.
How do you prove that a group of order 3 is cyclic?
Any group must have an identity element e. As it has order 3, it must have two other elements, a and b. Now, clearly, ab = e, for if ab = b, then a = e:abb-1 = bb-1, so ae = e, or a = e.This contradicts the givens, so ab != b. Similarly, ab != a, leaving only possibility: ab = e. Multiplying by a-1, b = a-1. So our group has three elements: e, a, a-1.What is a2? It cannot be a, because that would imply a = e, a contradiction of the givens. Nor can it be e, because then a = a-1, and these were shown to be distinct. One possibility remains: a2 = a-1.That means that a3 = e, and the powers of a are: a0 = e, a, a2 = a-1, a3 = e, a4 = a, etc. Thus, the cyclic group generated by a is given by: = {e, a, a-1}.QED.Let g be any element other than the identity. Consider , the subgroup generated by g. By Lagrange's Theorem, the order of is either 1 or 3. Which is it? contains at least two distinct elements (e and a). Therefore it has 3 elements, and so is the whole group. In other words, g generates the group.QEDIn fact here is the proof that any group of order p where p is a prime number is cyclic. It follow precisely from the proof given for order 3.Let p be any prime number and let the order of a group G be p. We denote this as|G|=p. We know G has more than one element, so let g be an element of the group and g is not the identity element in G. We also know contains more than one element and ||1 such that gn =1 if such an n exists.
Prove that the set of all real no is a group with respect of multiplication?
There are four requirements that need to be satisfied: A. Closure: For any two elements of the group, a and b, the operation a*b is also a member of the group. B. Associativity: For any three members of the group, a*(b*c) = (a*b)*c C. Identity: There exists an element in the group, called the identity and denoted by i, such that a*i = i*a for all a in the group. For real numbers with multiplication, this element is 1. D. Inverse: For any member of the group, a, there exists a member of the group, b, such that a*b = b*a = 1 (the identity). b is called the inverse of a and denoted by a-1.
How can you identify if a new substance is made?
You would use trend of the periodic table to pinpoint the group or period of the substance. Then you would use group/period characteristics. If you can not find an element that matches, you will have to repeat the process which you created the element(if you created it). If you found the element then search around for more and team-up with a renowned chemist and prove it. ***It could take a few years to a coule decades to prove it***
Who has to prove order of protection?
civil court
What qualifications does a bugler need?
In order to become a full time bugler in the military, you will need at least a high school education. You will also need to prove your proficiency in playing the bugle horn.
Why can a hypothesis never be proven?
It can be proven, you have to do at least 3 experiments to prove your hypothesis.
What element did Einstein believe could be used to prove his theory that mass and energy are interchange able?
radium
