The property that allows the separation of a sample of sand and seawater by filtration is particle size. Sand particles are larger and solid, while seawater is a liquid solution containing dissolved salts and smaller particles. When the mixture is passed through a filter, the sand is trapped on the filter paper, while the seawater passes through, effectively separating the two components based on their differing physical states and sizes.
The mass of a sample of matter can be decreased by removing some of its material, such as through evaporation, sublimation, or physical separation techniques like filtration or centrifugation. Additionally, chemical reactions that consume the sample can also result in a decrease in mass, such as combustion or decomposition. In specific contexts, such as nuclear reactions, mass can be converted into energy, effectively reducing the mass of the remaining sample.
Depends on what the sample is and how much of it you have.
Divide 158 by 156. The answer is the density in grams per ml. In this case, very close to 1 g/ml Density = MASS divided by VOLUME
You can filter it off using a sinted glass crucible, fine filter paper, a vacuum pump and a side-arm flask. If you don't have that sort of equipment: a filter funnel, filter paper and a conical flask should do.
An intensive physical property does not depend on the size of the sample. An example of an intensive physical property is density. An extensive physical property does depend on the size of the sample, such as mass and volume.
in gel filtration the volume of eluent is what moves compounds in and out of the pores in the matrix.A large volume of sample means the sample components will not be introduced to the matrix as a tight "plug" and the sample will slowly spread into the matrix meaning the beginning and the ending of the sample will be far apart meaning the sample will be spread out over the gel matrix resulting in poor resolution of that component from any other.
Yes, some filters allow this. Some pressure must be aplied, to counteract the osmotic pressure. For more information, do some reading on reverse osmosis.
The mass of a sample of matter can be decreased by removing some of its material, such as through evaporation, sublimation, or physical separation techniques like filtration or centrifugation. Additionally, chemical reactions that consume the sample can also result in a decrease in mass, such as combustion or decomposition. In specific contexts, such as nuclear reactions, mass can be converted into energy, effectively reducing the mass of the remaining sample.
To calculate the mass of a 600 ml sample of seawater, you need to know the density. If the density of seawater is approximately 1.025 g/ml, the mass can be calculated using the formula: mass = density × volume. Therefore, the mass of the seawater would be approximately 600 ml × 1.025 g/ml = 615 grams.
Filtration
Depends on what the sample is and how much of it you have.
Divide 158 by 156. The answer is the density in grams per ml. In this case, very close to 1 g/ml Density = MASS divided by VOLUME
Crystals may disappear during suction filtration of a sample crystallized from benzene if the crystals dissolve in the solvent being used for filtration, or if they break up into smaller particles that pass through the filter. This can happen if the crystals are not fully dried or if too much force is applied during filtration.
Mass is an extensive property, which depends only on the amount of matter in the sample, not on the composition of the sample.
The technique is simple: heating of the sample.
It is 1.0128 g/mL.
Seawater is not a substance in the traditional sense because it is a mixture of various substances including water, salts, minerals, and organic matter. These components can vary in concentration and composition depending on the location and conditions of the water.