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How is the delta Hvap used to calculate the mass liquid boiled by 1 kj of energy?
1kJ x 1/Hvap x g/mol liquid
What is the amount of BTUS the human body has at rest?
1 met = 1kcal/kg/hr 1kcal = 3.97 btu At rest, the human body expends about 0.8 met. So, a 70 kg person at rest generates 0.8 * (3.97 btu * 70 kg) every hour. That would be about 222 btu/hr, which is not a measure of watts, so.... Since 1 btu/hr = 0.293 watts, that same person generates 65.14 watts at rest.
How many joules in one kilowatt?
1 kWh = 3.6 x 106 joules. In engineering notation, that's 3.6E6.
How is the delta H fusion used to calculate the mass of solid thatt 1kJ of energy will melt?
The delta H of fusion, or enthalpy of fusion, is the amount of energy required to melt a unit mass of a solid at its melting point. To calculate the mass of solid that 1 kJ of energy will melt, you can use the formula: mass = energy / ΔH_fusion. By dividing the energy (1 kJ) by the delta H of fusion (in kJ/kg), you can determine the mass of the solid that can be melted by that amount of energy.
How is the hfusion used to calculate the mass of solid that 1kj of enery will melt?
The heat fusion (hfusion) is the amount of energy required to melt a unit mass of a solid at its melting point without changing its temperature. To calculate the mass of solid that 1 kJ of energy will melt, you can use the formula ( m = \frac{Q}{hfusion} ), where ( m ) is the mass, ( Q ) is the heat energy (1 kJ in this case), and ( hfusion ) is the heat of fusion for the specific solid. By rearranging the formula, you can determine the mass that can be melted with the given energy.
How is the fusion used to calculate the mass of solid that 1kj of energy will melt?
1kj x 1/H fusion x g/mol solid
How is the h fusion use to calculate the mass of solid that 1kj of energy will melt?
1kj x 1/H fusion x g/mol solid
What is the difference between kj and kcals?
The difference between kj and kcals is that 1 kcal is equals to 4.1858kj. The previous unit for food energy was kcal. It has been replaced by the SI unit, kj.
How many kilocalories of heat are needed to raise the temperature of 460 grams of water from 13 C to 45 C?
The specific heat capacity of water is 1 calorie/gram °C. To convert this to kilocalories, we divide by 1000, so 1kcal/kg°C. The temperature change is 45 - 13 = 32°C. Therefore, the heat required is 460g * 32°C * 1kcal/kg°C = 14720 kcal.
Is 3.25kcal the same amount of energy as 3.25jouls?
No, to convert from cal. to joules 1 cal. = 4.18400 joules , then 1KCal = (4.18400 *10^-3) joules so 3.25 kcal doesn't equal 3.25 Joules
How much calories burnt in a 30 minutes pranayama?
from some sites details are given as follows1)Bhastrika Pranayam 1KCal/2 minutes2)Kapalbhati 4 KCal/7 min3)Anulom Volom 3K.Cal/6 min
How is the delta Hvap used to calculate the mass liquid boiled by 1 kj of energy?
1kJ x 1/Hvap x g/mol liquid
How many kilojoules are there in 95.0 Calories?
95Cal/ 1cal/ 4.184j/ 1Kj Over this is in dimensional analyses 1000 cal. 1cal 1000 j The answer is 3.97*10^-4 Kj
How is the H fusion used to calculate the mass of solid that 1kJ of energy will melt?
The enthalpy of fusion of a substance (H fusion) tells us how much energy is required to melt one gram of the substance. By dividing the energy input (1 kJ) by the enthalpy of fusion, you can calculate the mass of the substance that the energy will melt. It's a simple ratio: mass = energy input (kJ) / enthalpy of fusion (kJ/g).
How is the Hvap used to calculate the mass of liquid boiled by 1 kJ of energy?
1kJ x 1/deltaHvap x g/mol liquid.
What is the amount of BTUS the human body has at rest?
1 met = 1kcal/kg/hr 1kcal = 3.97 btu At rest, the human body expends about 0.8 met. So, a 70 kg person at rest generates 0.8 * (3.97 btu * 70 kg) every hour. That would be about 222 btu/hr, which is not a measure of watts, so.... Since 1 btu/hr = 0.293 watts, that same person generates 65.14 watts at rest.
How is the Hfusion used to calculate the mass of solid that 1kJ of energy will melt?
1kJ 1/Hfusion g/mol solid
