It seems like your question contains some typos or uses a specific code or shorthand. If you're asking whether a particular chemical reaction has occurred, please clarify the chemicals or compounds involved. With more context or corrected terminology, I’d be happy to help!
The reaction represents the exchange of elements between nickel (Ni) and gold (Au) bromide, resulting in the formation of nickel bromide (NiBr2) and elemental gold (Au). In this process, three moles of nickel (Ni) displace gold from its bromide compound, producing three moles of nickel bromide and two moles of free gold. This type of reaction can be categorized as a single displacement reaction, where a more reactive metal replaces a less reactive metal in a compound.
Balanced:2 Ti + N2 ----> 2 TiN
In the formula 3Ni(OH)₂, each hydroxide (OH) group contains one oxygen atom. Since there are two hydroxide groups per nickel hydroxide unit and three units in total, the total number of oxygen atoms is 3 units × 2 oxygen atoms/unit = 6 oxygen atoms. Therefore, the formula 3Ni(OH)₂ represents 6 atoms of oxygen.
In the compound 3Ni(HCO₃)₂, there are 3 nickel (Ni) atoms, 6 carbon (C) atoms, 6 oxygen (O) atoms, and 6 hydrogen (H) atoms. This is calculated by recognizing that each formula unit of HCO₃ has 1 carbon, 3 oxygen, and 1 hydrogen, and since there are 2 HCO₃ groups in the formula, we multiply those quantities by 2. Thus, the total counts are 3 Ni, 6 C, 6 O, and 6 H.
Yes
Yes, the reaction between nickel (Ni) and gold(III) bromide (AuBr₃) can occur. In this reaction, nickel displaces gold due to its higher reactivity, forming nickel(II) bromide (NiBr₂) and elemental gold (Au). The balanced equation represents a single displacement reaction, where a more reactive metal displaces a less reactive metal from its compound. Therefore, the reaction is plausible under appropriate conditions.
The reaction represents the exchange of elements between nickel (Ni) and gold (Au) bromide, resulting in the formation of nickel bromide (NiBr2) and elemental gold (Au). In this process, three moles of nickel (Ni) displace gold from its bromide compound, producing three moles of nickel bromide and two moles of free gold. This type of reaction can be categorized as a single displacement reaction, where a more reactive metal replaces a less reactive metal in a compound.
No, the chemical equation is not balanced. Balancing it requires adjusting the coefficients of the compounds so that the number of each type of atom is the same on both sides of the equation.
This is a single displacement reaction, also known as a replacement reaction or a substitution reaction. In this reaction, aluminum (Al) replaces nickel (Ni) in nickel(II) bromide (NiBr2) to form aluminum bromide (AlBr3) and nickel (Ni).
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Balanced:2 Ti + N2 ----> 2 TiN
3Ni(NO2)2 (aq) + 2Na3PO4 (aq) = Ni3(PO4)2 (s) + 6NaNO3 (aq)
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In the formula 3Ni(OH)₂, each hydroxide (OH) group contains one oxygen atom. Since there are two hydroxide groups per nickel hydroxide unit and three units in total, the total number of oxygen atoms is 3 units × 2 oxygen atoms/unit = 6 oxygen atoms. Therefore, the formula 3Ni(OH)₂ represents 6 atoms of oxygen.
it is 50 meters deep also it is the hail and sleet over it 3ni waz here 5.30.09
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