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Chemical formula silver nitrate?

The chemical formula for silver nitrate is AgNO3.


Formula silver nitrate?

The chemical formula for silver nitrate is AgNO3.


What is the mass of silver in 3.4g AgNo3?

To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. From this, you can calculate the mass of silver (Ag) in AgNO3, which is 107.87 g/mol. Therefore, the mass of silver in 3.4g of AgNO3 is (107.87/169.87) * 3.4g.


Mass of silver in 3.4g AgNO3?

To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.


Is AgNO3 powder a solid?

AgNO3 powder is white but a little grey solid.


How many moles of AgNO3 does 85 grams of AgNO3 represents?

To find the number of moles, you need to divide the given mass (85 grams) by the molar mass of AgNO3 (169.87 g/mol). 85 grams of AgNO3 represents 0.500 moles.


What is the chemical formula of sliver nitrate?

The chemical formula of silver nitrate is AgNO3.


What is the correct formula for silver (I) nitrate?

The correct formula for silver (I) nitrate is AgNO3.


What percent of AgNo3 is silver?

Silver nitrate (AgNO3) is composed of 63.5% silver by mass.


What is the equation of ammonium nitrate and silver nitrate?

(NH4)NO3 + AgNO3 --> (NH4)NO3 + AgNO3


What is the net ionic equation of AgNO3 HNO3?

Silver nitrate doesn't react with nitric acid.


How many mL of .117M AgNO3 solution would be required to react exactly with 3.82 moles of NaCl?

Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can