AgNO3 powder is white but a little grey solid.
The silver nitrate solution (AgNO3) provides the silver in silver chloride.
Its name is silver nitrate octahydrate. silver(Ag) nitrite(NO2) * octahydrate (8H2O)
0.688 moles*6.02x1023=4.14x1023 Formula units
AgNO3
The chemical formula for silver nitrate is AgNO3.
The chemical formula for silver nitrate is AgNO3.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. From this, you can calculate the mass of silver (Ag) in AgNO3, which is 107.87 g/mol. Therefore, the mass of silver in 3.4g of AgNO3 is (107.87/169.87) * 3.4g.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.
AgNO3 powder is white but a little grey solid.
To find the number of moles, you need to divide the given mass (85 grams) by the molar mass of AgNO3 (169.87 g/mol). 85 grams of AgNO3 represents 0.500 moles.
The chemical formula of silver nitrate is AgNO3.
The correct formula for silver (I) nitrate is AgNO3.
Silver nitrate (AgNO3) is composed of 63.5% silver by mass.
(NH4)NO3 + AgNO3 --> (NH4)NO3 + AgNO3
Silver nitrate doesn't react with nitric acid.
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can