They are both from the same group, yes. But F is above Cl so it means that the F's valence shell is nearer the nucleus (or at "lower level") than the valence shell in Cl, which causes F to have more effective nuclear charge.
This fact explains the more electron affinity* in F in relation to Cl and therefore F is more reactive.
* - electron affinity refers to a free atom. electronegativity refers to an atom in a molecule.
It takes less energy to release Cl atoms than F atoms from CFCs because Cl has a larger atomic radius compared to F. This means that the bond between Cl and C in CFCs is weaker, requiring less energy to break. Additionally, Cl is lower in electronegativity than F, making it less likely to form strong bonds, further contributing to the lower energy needed to release Cl atoms.
in Cl the resonance occurs from 3p orbitals but in F resonance occurs from 2p orbitals due this reason F increase electron density in conjugate base more as compare to Cl .
Cl and F
Cl2, O has atomic number 8, Cl has atomic number 17 so in OCl- , there are 26 electrons. ClF has the same number of electrons, Cl atomic number 17, F atomic number 9- this is an interhalogen, chlorine monofluoride. A quick way is to look for an atom with an atomic number one higher (that's to compensate for the electron) than either Cl or O. You can ignore Cl as the atom with atomic number 18 is argon a noble gas- one higher than Cl is F.
The H-F bond is more polar than the H-I bond because F (fluorine) is more electronegative than I (iodine). It thus attracts the shared electrons more than does the I, making it a more polar bond.
The As-F bond will be more polar than the As-Cl bond. This is because fluorine is more electronegative than chlorine, leading to a greater difference in electronegativity between the atoms and a more polar bond.
F is the stronger base because it is bigger than Cl
It takes less energy to release Cl atoms than F atoms from CFCs because Cl has a larger atomic radius compared to F. This means that the bond between Cl and C in CFCs is weaker, requiring less energy to break. Additionally, Cl is lower in electronegativity than F, making it less likely to form strong bonds, further contributing to the lower energy needed to release Cl atoms.
in Cl the resonance occurs from 3p orbitals but in F resonance occurs from 2p orbitals due this reason F increase electron density in conjugate base more as compare to Cl .
bond energy (in kJ/mol) F-F:158 Cl-Cl: 244 Hence, in order of decreasing bond strength: Cl-Cl => => (F-F) => Fluorine is an anomaly. Bond strength decreases from chlorine to iodine as down the group, the atomic size becomes larger and thus the valence electron orbitals become more diffused, causing the overlap of orbitals to become less effective. Therefore the halogen-halogen bond becomes weaker. Fluorine is an exception due to its extremely small size. The F-F bond length is so short that the lone pairs of electrons on the fluorine atoms repel each other and weakens the F-F bond. I hope that answers your question.
Neon
A polar bond occurs when there is an unequal sharing of electrons between two atoms due to differences in electronegativity. In the given examples: F-F and Cl-Cl bonds are nonpolar because they have identical atoms sharing electrons. H-F and H-Cl bonds are polar due to the difference in electronegativity between hydrogen and fluorine/chlorine. P-S bond may be polar or nonpolar depending on the electronegativity of phosphorus and sulfur.
The oxidation number of Cl in ClF3 is +3. This is because fluorine (F) is more electronegative than chlorine (Cl) and will take on an oxidation number of -1, leaving chlorine with an oxidation number of +3 to balance the overall charge of the compound.
Chlorine has a larger atomic radius than fluorine. This is because chlorine has its outermost electrons in the 3rd energy level, which is farther from the nucleus, and fluorine has its outermost electrons in the 2nd energy level, which is closer to the nucleus.
You mostly want the temparuture at 75 F. This is when they will be the most active. Never get it more than 80 F. Never get it less than 60 F
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
The H-F bond is the most polar because fluorine is the most electronegative element among chlorine, bromine, and fluorine. The greater the electronegativity difference between the elements in a bond, the more polar the bond.