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One out of the five of Huckell's rules tells us that the molecule needs to be fully conjugated in order for it to be considered an aromatic molecule.

Looking at cycloheptatriene you can see that we have three double-bonds, each making two carbons sp2 hybridized. However, the seventh carbon is sp3 (the one that is not bonded to a double bond) so therefore fails Huckell's criteria and can not be considered aromatic.

The cycloheptatrienyl cation; however, converts this sp3-hybridized carbon in to an sp2-hybridized carbon, with an empty p-orbital.

We would then have the following:

1)Molecule needs to be planar - Check!

2)Molecule has 2 or more double-bonds - Check!

3)Molecule is monocyclic - Check!

4)Molecule is fully conjugated - CHECK!

5)Molecule has 4n+2 pi-electrons - Check!

.

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