Is cyclohexene an aromatic compound

Answer 1

One out of the five of Huckell's rules tells us that the molecule needs to be fully conjugated in order for it to be considered an aromatic molecule.

Looking at cycloheptatriene you can see that we have three double-bonds, each making two carbons sp2 hybridized. However, the seventh carbon is sp3 (the one that is not bonded to a double bond) so therefore fails Huckell's criteria and can not be considered aromatic.

The cycloheptatrienyl cation; however, converts this sp3-hybridized carbon in to an sp2-hybridized carbon, with an empty p-orbital.

We would then have the following:

1)Molecule needs to be planar - Check!

2)Molecule has 2 or more double-bonds - Check!

3)Molecule is monocyclic - Check!

4)Molecule is fully conjugated - CHECK!

5)Molecule has 4n+2 pi-electrons - Check!

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Answer 2

This is not an aromatic compound because it didn't satisfy two of the rules for aromaticity.

This ring has 4 double bonds, which means it has 8 electrons participating in pi bonding. According to Huckle's rule of 4n+2 number of electrons (n =0,1, etc), the only allowed numbers would be 2, 6, 10.... The fact that 8 does not fall in this these numbers means it can't be aromatic.

Another rule is that the molecule must be cyclic and planar. While this molecule is cyclic, it still bends to form a boat-like confirmation, thus it is not planar.

Answer 3

No, cyclohexene is not an aromatic compound. It is a cyclic alkene with one double bond in the ring structure, making it non-aromatic. Aromatic compounds are characterized by having a conjugated ring system with delocalized pi electrons, which cyclohexene does not exhibit.

Answer 4

No - it is cycloaliphatic.