This depends on the specific reaction.
Reactant
The formation of iron sulfide is a synthesis reaction because it involves the combination of iron and sulfur to produce iron sulfide as a single product. In this reaction, the two reactants combine to form a new compound, iron sulfide, without any additional byproducts.
Iron(II) sulfide is insoluble in water.
This depends on the reaction involved.
It appears to be a chemical equation where FeS (Iron(II) sulfide) reacts with HCl (Hydrochloric acid) to produce FeCl2 (Iron(II) chloride) and H2S (Hydrogen sulfide gas). It represents a chemical reaction where a solid reactant with an acid forms a different compound and a gas as products.
There is no elemental iron (Fe) involved in this reaction, neither as reactant (iron sulphide -FeS- plus oxygen are) nor as product (iron oxide (FeO) plus sulphur dioxide are)
Reactant
Iron sulfate can be both a reactant and a product in different chemical reactions. When iron reacts with sulfuric acid, iron sulfate is produced as a product. However, when iron sulfate reacts with other chemicals, it can also act as a reactant in the reaction.
Reactant.
Iron sulphate can be both a reactant and a product, depending on the chemical reaction. It can react to form different compounds or be produced from the reaction of iron and sulphuric acid.
The product of iron(II) and sulfur is iron(II) sulfide, with the chemical formula FeS.
Heating a mixture of iron and sulfur will result in the formation of iron sulfide, commonly known as iron (II) sulfide or ferrous sulfide. This is a black solid compound with the chemical formula FeS.
Iron(II) sulfide is formed by the reaction of iron and sulfur as follows: Fe + S --> FeS To determine the amount of iron(II) sulfide formed, we need to consider the limiting reactant, which is sulfur in this case. The molar mass of iron(II) sulfide is 87.91 g/mol. Therefore, if 40g of sulfur reacts, it will form 40g / (32.06g/mol) = 1.25 moles of iron(II) sulfide, which is equivalent to 1.25 x 87.91 = 109.89g. So, 109.89g of iron sulfide will be formed.
Iron reacts with sulfur to form iron sulfide, also known as pyrite or fool's gold. The chemical equation for this reaction is: Fe + S -> FeS.
The reaction between iron(II) sulfide (FeS) and hydrochloric acid (HCl) will produce iron(II) chloride (FeCl2), hydrogen sulfide gas (H2S), and water (H2O).
The balanced equation for the reaction of iron and sulfur to form iron sulfide is: Fe + S → FeS From the equation, we can see that 1 mole of iron reacts with 1 mole of sulfur to form 1 mole of iron sulfide. The molar mass of Fe is 55.85 g/mol and that of S is 32.07 g/mol. First, calculate the number of moles of Fe and S in the given masses. Then, determine which reactant is limiting based on the stoichiometry of the reaction. Finally, use the limiting reactant to calculate the amount of iron sulfide formed.
Ferrous Sulfide = Iron (III) Sulfide Both -> Fe2S3