Yes, it is possible for the average velocity of an object to be zero during some interval, even if its average velocity for the first half of the interval is not zero. This can occur if the object moves in opposite directions with equal distances during the two halves of the interval. For example, if a car moves 3 miles east in the first half of an hour and then moves 3 miles west in the second half of an hour, its average velocity for the entire hour would be zero.
It's 63.7 meters/second faster than its initial speed, downward, and 63.7 meters/second slower than its final speed, downward. Without knowing either of those, we can't calculate the specific number.
Average velocity is defined as the change in position of an object divided by the time taken to undergo that change. It gives a measure of how fast an object is moving in a particular direction over a given time interval. Mathematically, it is represented as: average velocity = (final position - initial position) / time.
Not at all. If it slows down or speeds up at any point, then it'll have different instantaneous velocity at different points, and its average velocity for some section of the line can be yet another different number. Simple example: A guy drives home from the office at a steady speed of 35 miles per hour. On the way, he stops buy a soda. His instantaneous velocity is zero during the stop, and 35 miles per hour whenever he's moving. His average velocity for the trip home is more than zero, and less than 35 miles per hour.
For the purposes of this explanation, velocity will be given in m/s. If it's starting position is the same as its stopping position, the radio controlled car will have an average velocity of zero meters per second. This is because average velocity is displacement/time interval. Displacement is change in position and is a vector quantity, which has magnitude and direction. Average velocity is the displacement/time interval, and is also a vector quantity, including the magnitude of the speed and its direction. If you start and stop walking at the same position, your displacement is 0m, even if you walked a distance of 100 miles, and your average velocity would be 0m/s. Refer to the related link below for an illustration.
Yes, it is possible for the average velocity of an object to be zero during some interval, even if its average velocity for the first half of the interval is not zero. This can occur if the object moves in opposite directions with equal distances during the two halves of the interval. For example, if a car moves 3 miles east in the first half of an hour and then moves 3 miles west in the second half of an hour, its average velocity for the entire hour would be zero.
The average velocity for an interval must be plotted at the middle of the time interval to represent an instantaneous velocity on a velocity-time graph.
Average velocity can be calculated by dividing the displacement (change in position) by the time interval. The formula for average velocity is average velocity = (final position - initial position) / time interval.
The instantaneous velocity is the limit of the average velocity, as the time interval tends to zero. If you are not familiar with limits, basically you make the time interval very small and calculate the average velocity.
The average velocity over an time interval is the average of the instantaneous velocities for all instants over that period. Conversely, as the time interval is reduced, the average velocity comes closer and closer to the instantaneous velocity.
The average velocity would be the total displacement over the total time interval. To calculate this, divide the total displacement by the total time to get the average velocity.
It equals an undefined entity. The average acceleration of an object equals the CHANGE in velocity divided by the time interval. The term "change in velocity" is not the same as the term "velocity", "average velocity", or "instantaneous velocity".
To find the average velocity during a 15-second interval, you would calculate the total displacement during that time and divide it by the total time. The formula for average velocity is displacement divided by time.
Average velocity equals the average speed if (and only if) the motion is in the same direction. If not, the average speed, being the average of the absolute value of the velocity, will be larger.
The speed of something in a given direction.
Yes, the velocity of an object at an instant of time can be greater than the average velocity over a time interval containing the instant, especially if the object is changing velocity rapidly. Similarly, it can also be less than the average velocity, especially if the object is reversing direction or slowing down during that time interval.
That's correct! The average acceleration of an object over a certain time interval is given by the slope of the line connecting the initial and final velocity points on a velocity vs. time graph during that interval. It is calculated by dividing the change in velocity by the time interval.