yes
The balanced equation for BaCO3 + 2HI is BaCO3 + 2HI → BaI2 + H2O + CO2.
The solubility of barium carbonate (BaCO3) in water is very low, approximately 0.0002 grams per 100 mL at room temperature. Therefore, in 1000 mL of water, about 0.002 grams of BaCO3 would dissolve. This indicates that BaCO3 is not soluble in water and will mostly remain undissolved.
The solubility of BaCO3 can be calculated by taking the square root of the Ksp value, which is 7.94 x 10^-5 mol/L. This represents the maximum amount of BaCO3 that can dissolve in water at equilibrium.
Barium carbonate (BaCO3) is most likely to precipitate since it is insoluble in water. When barium ions (Ba2+) and carbonate ions (CO32-) combine in solution, they form a solid precipitate of barium carbonate.
Yes.
BaCO3 is barium carbonate. It is a solid and is mostly insoluble in water.
BaCO3(s) → BaO(s) + CO2(g)
The chemical formula for Barium Carbonate is BaCO3
The balanced equation for BaCO3 + 2HI is BaCO3 + 2HI → BaI2 + H2O + CO2.
The correct formula for Barium carbonate is BaCO3.
To calculate the number of grams in 21.3 moles of BaCO3, you need to multiply the number of moles by the molar mass of BaCO3. The molar mass of BaCO3 is 197.34 g/mol. Therefore, 21.3 moles of BaCO3 would be 21.3 mol x 197.34 g/mol = 4201.662 g.
The balanced equation is: K2CO3(aq) + BaCl2(aq) -> 2KCl(aq) + BaCO3(s).
No, BaCO3 is a carbonate from the CO3 part of the compund
The balanced equation for sulfuric acid (H2SO4) reacting with barium carbonate (BaCO3) is: H2SO4 + BaCO3 -> BaSO4 + H2O + CO2
BaCO3
Barium Carbonate
one