it is maximum at the poles
The value of acceleration due to gravity (g) decreases as you move from the Equator towards the poles due to the centrifugal force caused by the Earth's rotation. At the Equator, this force counteracts some of the gravitational force, resulting in a lower g value compared to the poles.
Solar maximum can occur up to 42 degrees north of the equator as it did in 1859.
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
Maximum inclination of moon's orbit to the ecliptic = 5.3°Current inclination of the ecliptic to the celestial equator = 23.4°Moon's maximum declination = 5.3° + 23.4° = + 28.7°Maximum altitude of the celestial equator at 42° north latitude = 90° - 42° = 48°Moon's maximum altitude at 42° north latitude = 48° + 28.7° = 76.7°
The Equator is the latitude line with a given value of 0-degrees. There Equator runs completely around the Earth. There are 360-longitude lines that intersect the Equator.
at the poles
The value of acceleration due to gravity (g) decreases as you move from the Equator towards the poles due to the centrifugal force caused by the Earth's rotation. At the Equator, this force counteracts some of the gravitational force, resulting in a lower g value compared to the poles.
we know g equalls GM/R*R. Therefore g is inversly proportional to R spuare. Where R is radius of the planet. The R at the equator is the greatest. Hence the value of g is min at the equator. The value if g increases from the equator to the poles.
Yes, there is a difference in the value of acceleration due to gravity (g) at the equator and the poles. This is because the Earth is not a perfect sphere and has an oblate shape. At the equator, the centrifugal force due to the Earth's rotation reduces the effective gravity and makes g slightly smaller compared to the poles where this effect is minimal.
The RGB to HSV formula for converting colors is as follows: To convert RGB to HSV: Find the maximum and minimum values of R, G, and B. Calculate the value (V) by dividing the maximum value by 255 and multiplying by 100. Calculate the saturation (S) by subtracting the minimum value from the maximum value, dividing by the maximum value, and multiplying by 100. Calculate the hue (H) based on the maximum color component: If the maximum is R, then H 60 ((G - B) / (max - min)) (mod 360) If the maximum is G, then H 60 ((B - R) / (max - min)) 120 If the maximum is B, then H 60 ((R - G) / (max - min)) 240 This formula allows you to convert RGB values to HSV values, which represent colors in terms of hue, saturation, and value.
Solar maximum can occur up to 42 degrees north of the equator as it did in 1859.
What is maximum value
Gravitational potential is maximum at poles.
On Earth:Do you mean acceleration due to gravity?Here is your answer minimum value of g=9.8m/s2maximum value =10m/s2 approximately.Elsewhere:Anything positive and finite is theoretically possible.
value of acceleration due to gravity is maximum at the surface of earth. So the gravitational field strength. as g'=g(1-d/R) at surface d=R so d=R so g'=g at earth's centre g=0. Its value decrease with decrease or increase in height. as: g'=g(1-2h/R) ......for height h and g'=g(1-d/R) .....for depth d
g will increase when rotation is stopped because:- g depend on following thing;:- first on shape of earth second on rotation....(only Equator) not pole third one on going altitude and depth,...........
The value of g depends on latitude because the Earth is wider at the equator than at the poles. g = 9.80612 - 0.025865 cos (2 x latitude) metres/sec/sec It expresses how quickly an object accelerates after being dropped. The formula gives 9.7802 at the equator and 9.8320 at the poles. The weight of a 1 kg mass is g Newtons.