False. The Sun radiates electromagnetic energy in all parts of the spectrum, not just the tiny sliver that is "visible light". Additionally, the Sun gives off hard radiation in the form of alpha and beta particles, and a considerable "solar wind" of charged atomic nuclei.
Bioluminescence - if it gives of visible light. However heat is also light and metabolism itself therefore gives off light, but you can not see it because it is infrared light.
The visible light emitted by the Sun originates from the photosphere, which is the outermost layer of the Sun's atmosphere. This is the layer that we see when we observe the Sun from Earth.
UV has a HIGHER frequency than visible light. If you get such results, either you are not measuring the correct light, or something else is wrong with the measurement.
Visible light is just a small portion of the electromagnetic spectrum, which ranges from radio waves at the low-energy end to gamma rays at the high-energy end. Compared to other regions, visible light has wavelengths between approximately 400 to 700 nanometers, which is longer than ultraviolet light but shorter than infrared light. This range is perceptible to the human eye, while other regions, such as ultraviolet or infrared, are not visible but can have significant effects, like causing sunburn or enabling night vision, respectively.
Fluorescent materials, phosphorescent materials, and objects containing fluorescent dyes or pigments can emit visible light when exposed to ultraviolet light. This phenomenon occurs as the ultraviolet light excites the molecules within these materials, causing them to re-emit visible light at a longer wavelength.
The photosphere gives off heat and visible light.
Assuming that you mean light in the visible spectrum, it would mean that the thing is giving of radiation that is in the visible light spectrum
Bioluminescence - if it gives of visible light. However heat is also light and metabolism itself therefore gives off light, but you can not see it because it is infrared light.
White light contains all of the colors in the visible spectrum. Black contains none of these colors.
The visible light emitted by the Sun originates from the photosphere, which is the outermost layer of the Sun's atmosphere. This is the layer that we see when we observe the Sun from Earth.
Yes, that's correct.
UV has a HIGHER frequency than visible light. If you get such results, either you are not measuring the correct light, or something else is wrong with the measurement.
To give out light means to emit photons or electromagnetic radiation in the visible spectrum, making an object or source visible to the human eye. Light can be produced naturally (such as sunlight) or artificially (such as light bulbs or LEDs).
Fluorescent materials, phosphorescent materials, and objects containing fluorescent dyes or pigments can emit visible light when exposed to ultraviolet light. This phenomenon occurs as the ultraviolet light excites the molecules within these materials, causing them to re-emit visible light at a longer wavelength.
"Most is visible light" is false. Visible light is but a small part of the electromagnetic spectrum. Also, "vera" is not a valid SI prefix. Perhaps you mean "tera", which is 1012.
The sun is the only object in the solar system that generates and emits visible light. Any of the others is a correct answer to this question.
No, infrared radiation (IR) does not have a higher frequency than visible light. Visible light is above IR on the electromagnetic spectrum. It (visible light) has higher frequency and shorter wavelengths than IR radiation does.