The most noteworthy is the San Andreas fault.
If a fault or intrusion cuts through an unconformity, the fault or intrusion is younger than all the rocks it cuts through above and below the unconformity.
The relative age of a fault or igneous intrusion that cuts through an unconformity is younger than the unconformity but older than the rock it cuts through. This is because the fault or intrusion must have formed after the deposition of the rock layers below the unconformity but before the deposition of the rock layers above the unconformity.
A fault must be younger than the rock it cuts through.
To determine whether the fault occurred before or after the igneous intrusion, geologists typically analyze the relationships between the rock layers and the intrusion. If the fault cuts through the igneous rock, it indicates that the fault occurred after the intrusion. Conversely, if the intrusion is found within the fault zone or is displaced by the fault, it suggests that the fault predates the igneous intrusion.
To determine whether the fault is older or younger than rock layer A, we can use the principle of cross-cutting relationships. If the fault cuts through rock layer A, it is younger than that layer, as it must have formed after the rock was deposited. Conversely, if rock layer A is found to be disrupted by the fault, then the fault is older. Therefore, examining the relationship between the fault and rock layer A is key to establishing their relative ages.
If a fault or intrusion cuts through an unconformity, the fault or intrusion is younger than all the rocks it cuts through above and below the unconformity.
The relative age of a fault or igneous intrusion that cuts through an unconformity is younger than the unconformity but older than the rock it cuts through. This is because the fault or intrusion must have formed after the deposition of the rock layers below the unconformity but before the deposition of the rock layers above the unconformity.
A fault is necessarily younger than faults it cuts through; it could not have happened if the layers were not there first.
The Colorado River.
A fault must be younger than the rock it cuts through.
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I think so as Arnold make taxes cuts
The law of cross-cutting relationships.
The law of cross-cutting relationships.
The New Madrid fault systems extends 120 miles southward from the area of Charleston, Missouri, and Cairo, Illinois, through New Madrid and Caruthersville, following Interstate 55 to Blytheville and on down to Marked Tree, Arkansas. It crosses five state lines and cuts across the Mississippi River in three places and the Ohio River in two places. The San Andreas Fault in California is about 810 miles long, and the Cascadi Fault just offshore from Oregon and Washington is about 650 miles long. (Sorry for the finger-check - it should be the Cascadia Fault.
How could the rock be faulted if it came after the faulting? It wouldn't be there to fault. So therefore, what ever the fault cuts through, it must be younger than it in order for it to be able to cut the rock in the first place.
What is the relative age of a fault that cuts across three horizontal sedimentary rock layers?A. The fault is older than the middle layer. B.The fault is younger than all the layers it cuts across.C. The fault is the same age as the top layer. D. The fault is older than all the layers it cuts across == ==