Noble gas configuration of beryllium

Answer 1

The electron configuration of barium (atomic number 56) can be written three different ways:

- Full configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2

- Compressed (without all standard script numbers): 1s2 2s2p6 3s2p6d10 4s2p6d10 5s2p6 6s2

- Noble Gas form : [Xe] 6s2 (this works because [Xe] symbolizes the electronic configuration of Xenon, which is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6. When added to 6s2, it is equivalent to the full electron configuration of Barium, when neutral.)
The electronic configuration for barium is [Xe] 6s^2 2, 8, 18, 18, 8, 2.

Answer 2

You first look at Barium's location on the Periodic Table: 6th period down, second group across. This puts it in the s block of the periodic table, which includes the first two vertical groups. Then you move back across the periodic table, looking at each lower element's atomic number until you reach a noble gas. Barium is element 56, so looking at element 55 we come across cesium. Going one lower and looking at element 54, we reach xenon, Xe, which is a noble gas. This is the basis behind the name "noble gas notation." Since xenon is the heaviest noble gas that is lighter than barium, we begin the notation with the symbol for xenon in brackets: [Xe]. Since barium is the second element over in the s block and the 6th period down, we can expand this to [Xe]6s2, which is the complete noble gas notation.

Answer 3

The electronic configuration of barium is [Xe] 6s2

It can achieve a noble gas configuration only by losing two electrons (as in Ba2+ ion)

Answer 4

The noble gas configuration of beryllium (Be) is [He] 2s^2. This means it has the same electron configuration as helium (He), with a filled 1s orbital and two electrons in the 2s orbital.

Answer 5

[He] 2s2 2p1

Answer 6

[Xe] 6s2

Answer 7

[He]2s2

Answer 8

[Xe]6s2

Answer 9

[Xe]6s2